Answer:
7.71 × 10⁻⁴ M/s
Explanation:
The initial rate of the reaction can be expressed by using the formula:
![\dfrac{\Delta [O_2]}{\Delta t}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5CDelta%20%5BO_2%5D%7D%7B%5CDelta%20t%7D)
where the number of moles of O₂ = 
where;
Pressue P = 1.00 atm
Volume V =5.74mL = (5.74 /1000) L
Rate R = 0.082 L atm/mol.K
Temperature = 298 K
= 2.35 × 10⁻⁴ mol
Δ[O₂] = 
Δ[O₂] = 
Δ[O₂] = 0.04626 M
The initial rate =
= 
= 7.71 × 10⁻⁴ M/s
I think it is calcium carbonate, from sedimentary rocks and such
It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:
Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH)
With the values put in: 0.35 x 45 = 0.35 x V(NaOH)
= 45 ml.
There is 45 ml of V(NaOH)
Let me know if you need anything else. :)
- Dotz
The simple principle for solute dissolution in a particular solvent is "like dissolves like". In the case of water, a solute will dissolve if it is polar. This is because water is a polar solvent. A polar substance is one which has particles that have a net charge on them. This net charge produces forces of attraction. When a polar solute is added to water, the water molecules are attracted to the solute particles and they attach to them. After attaching to the water molecules, the solute particles are dispersed throughout the water. Therefore, the answer is molecules or ions of a solute spread throughout the water molecules<span>.</span>
