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Serjik [45]
1 year ago
5

Why do we experience lower temperature during ber months up to febuary?

Chemistry
1 answer:
Mashutka [201]1 year ago
5 0

Hope you might understand

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Hi, can someone help me with this.
AleksAgata [21]
It is 0.5474 but you can put 0.5 hope this helps
4 0
3 years ago
What is nitrogen state at 20 celcius
SpyIntel [72]
Hi there, I believe that nitrogen turns into a liquid at 20 degrees Celsius. Thererore, the nitrogen state is liquid.
7 0
3 years ago
Write an equation that shows the reaction between acetic acid and triethylamine (CH3CH2)3N. Draw all non-bonding lone electron p
Anni [7]

Answer:

-) Acid-base reaction

-) Carboxylic acid, alcohol, alkene and ketone

Explanation:

For the reaction between acetic acid and triethylamine, we will have an <u>acid-base reaction</u>. Therefore a s<u>alt would be produced</u> in this case an  <u>"ammonium quaternary salt"</u>. Also, we have to remember that on this reaction the acid is the acetic acid and the base is the triethylamine. See figure 1

For the second question, we have to check the <u>structure of Prostaglandin</u> E1 in which we have the functional groups:

<u>1) Carboxylic acid</u>

<u>2) Alcohol</u>

<u>3) Alkene</u>

<u>4) Ketone</u>

See figure 2.

I hope it helps!

8 0
3 years ago
What is the molarity of a solution that contains
EastWind [94]

Explanation:

no. of molea of Ca(NO3)2 = given mass/molar mass

no. of moles= 92/ 164 = 0.56 mol

formula=

Molarity = moles of solute /solution in litres

Molarity = 0.56/ 0.4

=1.4 M

hope it helped!

8 0
3 years ago
Consider this reaction. What volume of oxygen gas, in milliliters, is required to react with 0.640 g of SO2 gas at S TP? 11.2 mL
DedPeter [7]

Answer:

112mL

Explanation:

We'll begin by calculating the number of mole in 0.640g of SO2.

This is illustrated below:

Molar mass of SO2 = 32 + (16x2) = 64g/mol

Mass of SO2 = 0.640g

Number of mole of SO2 =.?

Mole = mass /molar mass

Number of mole of SO2 = 0.640/64

Number of mole of SO2 = 0.01 mole

Next, we shall determine the number of mole of O2 required for the reaction. This is illustrated below:

2SO2(g) + O2(g) —> 2SO3(g)

From the balanced equation above,

2 moles of SO2 reacted with 1 mole of O2.

Therefore, 0.01 mole of SO2 will react with = (0.01 x 1)/2 = 0.005 mole of O2.

Therefore, 0.005 mole of O2 is required for the reaction.

Finally, we shall determine the volume of O2 required for the reaction as follow:

Note: 1 mole of a gas occupy 22.4L (22400mL) at stp.

1 mole of O2 occupy 22400mL at stp.

Therefore, 0.005 mole of O2 will occupy = 0.005 x 22400 = 112mL

Therefore, 112mL of O2 is required for the reaction.

5 0
3 years ago
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