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Serjik [45]
1 year ago
5

Why do we experience lower temperature during ber months up to febuary?

Chemistry
1 answer:
Mashutka [201]1 year ago
5 0

Hope you might understand

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Please help is for today
love history [14]

Answer:

Our bodies are designed to regulate our temperature. When it's cold outside, your body makes sure to keep the blood flowing to your core and vital organs to keep them warm. This can change the amount of blood flow to your hands and feet, making them feel cold

5 0
3 years ago
A Lewis acid is a substance that can
katrin2010 [14]
Accept a pair of nonbonding electrons,a Lewis acid is an electron-pair acceptor. A Lewis<span> base is any </span>substance, such as the OH-<span> ion, that </span>can<span> donate a pair of nonbonding electrons. </span>A Lewis<span> base is therefore an electron-pair donor.</span>
6 0
3 years ago
Which substances will make a salt when combined? (2 points) Vinegar and antacids Soda and wine Soap and ammonia Fertilizer and d
SCORPION-xisa [38]

vinegar and antacids.

7 0
2 years ago
Read 2 more answers
Water can form a solution by mixing with:
MA_775_DIABLO [31]

Explanation:

Solid, liquids and gases

8 0
3 years ago
Read 2 more answers
HNO3 + S --&gt; H2SO4 + NO Now identify the element oxidized and the element reduced. Which element is oxidized? Which element i
OleMash [197]

<u>Answer:</u> S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

<u>Explanation:</u>

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.

For the given chemical reaction:

HNO_3+S\rightarrow H_2SO_4+NO

<u>On the reactant side:</u>

Oxidation number of H = +1

Oxidation number of N = +5

Oxidation number of O = -2

Oxidation number of S = 0

<u>On the product side:</u>

Oxidation number of H = +1

Oxidation number of N = +2

Oxidation number of O = -2

Oxidation number of S = +6

As the oxidation number of S is increasing from 0 to +6. Thus, it is getting oxidized. Similarly, the oxidation number of N is decreasing from +5 to +2. Thus, it is getting reduced.

The oxidation numbers of O and H remain the same on both sides of the reaction. Thus, they are neither getting oxidized or reduced.

Hence, S is getting oxidized, N is getting reduced and O and H undergo no oxidation or reduction

3 0
2 years ago
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