Answer: n=2,l=1,ml=1 n=3,l=2,ml=0 n=3,l=3,ml=2 n=4,l=2,ml=0.
Explanation:
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Answer:
Mass of KNO3 in the original mix is 146.954 g
Explanation:
mass of
in original 254.5 mixture.
moles of 
moles of
= 0.2926 mol of BaSO4
Therefore,
0.2926 mol of BaCl2,
mass of 
= 60.92 g
the AgCl moles 

= 1.3891 mol of AgCl
note that, the Cl- derive from both,
so
mole of Cl- f NaCl
mol of Cl-
mol of NaCl = 0.8039 moles

then
KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3
Mass of KNO3 in the original mix is 146.954 g
Answer: 40.3 L
Explanation:
To calculate the moles :
According to stoichiometry :
1 moles of
produces = 3 moles of
Thus 0.600 moles of
will produce=
of
Volume of
Thus 40.3 L of CO is produced.
1 mole contains = 6.02x10^23 atoms. 0.31mole contains = 0.31x6.02x10^23 = 1.8662x10^23.