All categories

3 years ago

Please help me.balance this equation Al + 0(2) = Al0(3)

1 answer:

4 0

What helps me to balance equations is to list the elements i have on each side of the equation, and use tally marks to see what I have and don't have. Then when I'm done balancing, I tally again to make sure everything matches up.
On the left side, you have 1 Al, and 2 O. On the right side, 1 Al and 3 O.
In order for the equation to balance, you need to place a 2 in front of the AlO on the right side. This would make the Al have 2 atoms and the O have six. On the left side, you need to place a 2 in front of the Al and a 3 in front of the O, making it six. Left side: 2 Al's 6 O's. Right side: 2 Al's and 6 O's. Matches!

You might be interested in

Give five examples of structures with this formula (c6h12). at least one should contain a ring, and at least one should contain

hammer [34]

Answer: -

Following are five examples of structures with the chemical formula C₆H₁₂

Compound A is Hexene.

Compound B is 2-Hexene.

Compound C is 3-Hexene.

Compound D is Cyclohexane.

Compound E is Methylcyclopentane.

As we can see Hexene, 2- Hexene and 3-Hexene all have double bonds.

Cyclohexane and Methylcyclopentane contains a ring.

7 0

3 years ago

Write the isotope notation for the following isotope: copper-63, copper-65, magnesium-24, magnesium-25, magnesium-26, lithium-6,

andrey2020 [161]

63/29 Cu (copper-63)
65/29 Cu (copper-65)
24/12 Mg (magnesium 24)
25/12 Mg (magnesium 25)
26/12 Mg (magnesium 26)
6/3 Li (lithium 6)
7/3 Li (lithium 7)

The top number is the mass number and you find that by adding the number of neutrons and atomic number
The bottom number is the atomic number and it’s the number or protons

3 0

2 years ago

What is the energy of a wave with wavelength of 4.2 x 10-7 m. (Hint: Calculate for frequency first.)

erik [133]

Answer:

Option B. 4.74×10¯¹⁹ J.

Explanation:

The following data were obtained from the question:

Wavelength (λ) = 4.2×10¯⁷ m

Energy (E) =.?

Next, we shall determine the frequency of the wave. This can be obtained as follow:

Wavelength (λ) = 4.2×10¯⁷ m

Velocity (v) = constant = 3×10⁸ m/s

Frequency (f) =.?

v = λf

3×10⁸ = 4.2×10¯⁷ × f

Divide both side by 4.2×10¯⁷

f = 3×10⁸ / 4.2×10¯⁷

f = 7.143×10¹⁴ s¯¹

Therefore, the frequency of the wave is 7.143×10¹⁴ s¯¹.

Finally, we shall determine the energy of the wave using the following formula

E = hf

Where

E is the energy.

h is the Planck's constant

f is the frequency

Thus, the enery of the wave can be obtained as follow:

Frequency (f) = 7.143×10¹⁴ s¯¹.

Planck's constant = 6.63×10¯³⁴ Js

Energy (E) =..?

E = hf

E = 6.63×10¯³⁴ × 7.14×10¹⁴

E = 4.74×10¯¹⁹ J

Therefore, the energy of the wave is 4.74×10¯¹⁹ J.

5 0

3 years ago

Please help, need answer

defon

I would say the first three. But I'm not 100% sure. I'm truly sorry if it's wrong

8 0

2 years ago

An empty water bottle is full of air at 15°C and standard pressure. The volume of the bottle is 0. 500 liter. How many moles of

drek231 [11]

The moles of gas in the bottle has been 0.021 mol.

The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

$PV=nRT$

<h3>Computation for the moles of gas</h3>

The gi<em>ve</em>n gas has standard pressure, $P=1\rm atm$

The volume of the gas has been, $V= 0. 500 \;\rm L$

The temperature of the gas has been, $T=15^\circ \text C\\
T=288\;\rm K$

Substituting the values for the moles of gas, <em>n:</em>

<em />

<em /> $\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\
\textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\
\textit n=0.021\;mol$

The moles of gas in the bottle has been 0.021 mol.

Learn more about ideal gas, here:
brainly.com/question/8711877

5 0

2 years ago