Answer:
4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.
Explanation:
Half life (t1/2) = 8 days
Original mass (No) = 64 g
Elapsed time (t) = 32 days
Mass remaining (Nt) = ?
Using the half life equation we can obtain the mass remaining (Nt)
Nt = No (1/2) ^t/t1/2
Substituting the values, we have;
Nt = 64 * ( 1/2 ) ^32/8
Nt = 64 * (1/2) ^4
Nt = 64 * 0.0625
Nt = 4 g
So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.
You didn’t show the cylinder containing water, so I created one that you can use as a model (see image).
The water level was originally at 37 mL.
Then you added the ball, and it displaced its volume of water.
The new volume reading is 52 mL, so
Volume of ball = volume of displaced water = 52 mL – 37 mL = 15 mL.
Answer : The age of the artifact is, 
Explanation :
Half-life = 5715 years
First we have to calculate the rate constant, we use the formula :
Now we have to calculate the time taken to decay.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = time taken by sample = ?
a = initial activity of the reactant = 58.2 counts per minute
a - x = activity left after decay process = 42.8 counts per minute
Now put all the given values in above equation, we get
Therefore, the age of the artifact is,
The molecules vibrate when the substance is heated, and the shape of the substance begins to form a different shape. For example: when you hear up metal it will melt becuase its molecules are changing and moving.
Answer:
The correct option is: A) N₂
Explanation:
The Bond length of a chemical bond is the length of a chemical bond formed between two given atoms.
<u>Bond length is inversely proportional to the bond order</u> of the chemical bond, which is the total number of bonds between two atoms. <u>Thus as the bond order increases, the bond length decreases.</u>
A) N₂: The nitrogen-nitrogen bond in dinitrogen is a triple bond (N≡N).
Thus the bond order = 3.
B) O₂: The oxygen-oxygen bond in dioxygen is a triple bond (O=O).
Thus the bond order = 2.
C) SO₂: Sulfur dioxide is a resonance stabilized molecule and its resonance hybrid shows that the sulfur-oxygen bond in sulfur dioxide is a partial double bond.
Thus the bond order = 1.5
D) SO₃: Sulfur trioxide is a resonance stabilized molecule and its resonance hybrid shows that the sulfur-oxygen bond in sulfur trioxide is a partial double bond.
Thus the bond order = 1.33
<u>Since the bond order of N₂ is the largest, therefore, the N-N bond length is the shortest.</u>
