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Flauer [41]
3 years ago
13

Which compound is an acid? A. C2H4 B. KCl C. NH3 D. HNO3

Chemistry
2 answers:
Katyanochek1 [597]3 years ago
5 0
Nitric acid is option D.
Musya8 [376]3 years ago
4 0
<span> D. HNO3 is the compound that is an acid.

Glad to help.


-Jurgen</span>
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The activation energy for the reaction NO2 (g )+ CO (g) ⟶ NO (g) + CO2 (g) is Ea = 218 kJ/mol and the change in enthalpy for the
madreJ [45]

Answer:

470\frac{KJ}{mol}

Explanation:

The activation energy represents the energy barrier that reagents must pass to transform into products (or products to transform into reagents in a reverse reaction)

For any reaction, the change in enthalpy is related to the activation energy by the equation

\Delta H =E_{a\ direct}-E_{a\ reverse}

So, the activation energy for the reverse reaction is

E_{a\ reverse}=E_{a\ direct}-\Delta H =218 \frac{KJ}{mol} - (-252)\frac{KJ}{mol}=470\frac{KJ}{mol}

4 0
3 years ago
What would be the greatest difference in using an open ceramic coffee mug rather than an insulated mug with a lid as a calorimet
STALIN [3.7K]

Answer:

Hi. Increased evaporation would be the greatest difference.

Explanation:

Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.

6 0
2 years ago
Read 2 more answers
Which of the following is the correct formula for sulfuric acld?
Alona [7]

Explanation:

The answer is H2SO4 for sulphuric acid

6 0
3 years ago
What is the mass of 0.257 mol of calcium nitrate?
poizon [28]

Answer: 42.14 g

Explanation:      calcium nitrate -  Ca(NO_{3} )_{2}

                   , the molar mass of calcium nitrate = 164 g

<h3>                   formula used = given mass/molar mass= no of moles </h3>

                   mass required =0.257*164

                                               =42.14 g

                     

             

4 0
1 year ago
How many moles of KOH are required to produce 4.79 g K3PO4 according to the following reaction? 3KOH + H3PO4 -----&gt; K3PO4 + 3
8_murik_8 [283]

Answer:

0.677 moles

Explanation:

Take the atomic mass of K = 39.1, O =16.0, P = 31.0

no. of moles = mass / molar mass

no. of moles of K3PO4 used = 4.79 / (39.1x3 + 31 + 16x4)

= 0.02256 mol

From the equation, the mole ratio of KOH : K3PO4 = 3 :1,

meaning every 3 moles of KOH used, produces 1 mole of K3PO4.

So, using this ratio, let the no. of moles of KOH required to be y.

\frac{3}{1} =\frac{y}{0.02256} \\

y = 0.02256 x3

y = 0.0677 mol

If you don't find exactly 0.677 moles as one of the options, go for the closest one. A very slight error may occur because of taking different significant figures of atomic masses when calculating.

5 0
3 years ago
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