From ideal gas equation that is pv =nRt
n=number of moles which can be written as the ratio between the weight of a gas that is mass and its molecular mass n=m/Mm
pv=(m/Mm)RT
density is=mass per unit volume
P=m/v by arranging the equation we get
R =0.082atm/mol/k
Mm=pRT/P=[(1.10 x10^-6 x1000g/l) xo.082 atm/mol/k x(80+273] /(1.00 x10^-3) =31.84 to the nearest ten is 32
hence the gas is oxygen
Answer: 1.52 atm
Explanation:
Given that:
Volume of gas V = 10.0L
Temperature T = 35.0°C
Convert Celsius to Kelvin
(35.0°C + 273 = 308K)
Pressure P = ?
Number of moles = 0.6 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 10.0L = 0.6 moles x (0.0821 atm L K-1 mol-1 x 308K)
p x 10.0L = 15.17 atm L
p = 15.17 atm L / 10.0L
p = 1.517 atm (round to the nearest hundredth as 1.52 atm)
Thus, the pressure of the gas is 1.52 atm
Answer:
40 electrons
Explanation:
The element of zirconium (Zr) has an atomic number of 40, which means it has 40 protons and 40 electrons. It also has a molar mass of 91.224 g/mol.
It’s 1:1 b3cuae that’s the one u can
Answer:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)
Explanation:
Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:
- an equilibrium constant is, first of all, a fraction;
- in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
- in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
- each concentration should be raised to the power of the coefficient in the balanced chemical equation;
- only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.
Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)