An atom is unlikely to react when it is stable. That is when it's shell is complete. Due to the completion of the shell, no other electron can combine through any form of bonding. Hope i helped.
Answer:
B. misalignment of the chromosomes during anaphase I
Explanation:
Aneuploidy refers to an error in the chromosomal number of a cell. This occurs when the chromosomes fail to separate equally into individual cells, a process called MEIOTIC NONDISJUNCTION. Meiotic disjunction can occur in either the anaphase stage of meiosis I or meiosis II, however, different outcomes are produced.
When chromosomes fail to separate at meiosis I, it results in two gametes that lack that particular chromosome (n-1) and two gametes with two copies of the chromosome (n+1). This means that the four daughter cells will have an incorrect number of chromosomes, hence, the misalignment of the chromosomes during anaphase I will result in four aneuploid daughter cells.
Strong bases
Explanation:
KOH, CsOH and Ca(OH)₂ are all strong bases because they dissociate completely in aqueous solution.
A base is a substance that produces excess hydroxyl ions in aqueous solutions.
Strong bases would dissociate completely when in solution.
Bases of alkali and alkali earth metals are classified as strong because they exhibit full ionic characteristics.
They give full metals ions and hydroxide in solution.
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Bases brainly.com/question/5613072
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