Let's consider what we are asked. The domain is defined as a set of points that satisfy the equation on the x-ordinate.
So, essentially, we need to find if and what the restriction on x is.
Let's now consider just f(x) because g(x) is completely irrelevant to the question.
f(x) = 2 - x^(1/2)
Since f(x) can never be 0 for a defined function, let's consider when f(x) = 0 to find a restriction on x.
2 - x^(1/2) = 0
2 = x^(1/2)
+-4 = x
But we can only take the positive 4 because inside a square root has to always be positive (unless you're dealing with complex numbers), so the only restriction is that x cannot be equal to 4.
Therefore, our domain is: x >= 0; x =/= 4
Answer:
Step-by-step explanation:
a) (2³ · 2⁴)⁵ · (2⁷ · 2¹ · 2²)⁰ / (2³ · 2²) = (2⁷)⁵ · 1 / 2⁵ = 2³⁵ / 2⁵ = 2⁷
b) (((-6)²· (-6)⁴)³ / ((-2)² · 3²) · (-6)⁰ = ((6²· 6⁴)³ / (2²· 3²) 1 = (6⁶)³ / 6² = 6¹⁸ / 6² = 6¹⁶
c) (√81 / √9) · (3² / 3²) / 3² = (9 / 3) · 3²⁻² / 3² = 3 · 3⁰ / 3² = 3¹ / 3² = 1 / 3 = 3⁻¹
D) (√2 ·√3 ·√20) / √√625 = √6 · √20 / √25 = √6 · √5 · √4 / 5 = (2/5) √30
God is with you!!!
Answer:
Lesser x = -7
Greater x = 7
Step-by-step explanation:
g(x)= -10x² + 490
don't ask me Khan academy says so