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svlad2 [7]
3 years ago
8

Which line segment is a radius of circle F? BE AC AB BF

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0
I think the best answer is AB
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Brittany will be working full time this summer to save for her goal of having $10,000 by the time shes 21. Brittany has an accou
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7 0
2 years ago
If three times a number is increased by 24, the result is 16 less than seven
Marta_Voda [28]

Answer:

3X+24=7X-4

3X-7X=-4-24

-4X=-28

X=-28/-4

X=7 ANS.

PROOF:

3*7+24=7*7-4

21+24=49-4

45=45

Step-by-step explanation:

6 0
3 years ago
A study reported that the average age of menarche of girls entering the first year class of a small American private college in
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Answer:

Null hypothesis: \mu = 11.89

Alternative hypothesis: \mu \neq 11.89

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=12.98 represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=30 represent the sample size  

Solution to the problem

For this case we want to test the following hypothesis:

Null hypothesis: \mu = 11.89

Alternative hypothesis: \mu \neq 11.89

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

4 0
3 years ago
Simplify the following polynomial and write the answer in standard form. (9-2x^3+5^2-4x+5) - (-2x^3+2x-3)
pogonyaev
If I am reading the question correctly it would come out to -6x+42  First do all the addition and squaring, then factor in that negative.  You come out to -2x^3 +2x^3-4x-2x+25+5+9+3.  The x^3's cancel, the -x's add to -6x, then all that other adds to 42.
7 0
3 years ago
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Suppose a new car is purchased for $46,357 and depreciates by 22% over the first year of ownership. If the car is driven 12,170
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Answer:check the pic

Step-by-step explanation:

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3 years ago
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