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allsm [11]
3 years ago
8

Solve 80/100 = 68/n using cross multiplication.

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0

80n = 68*100

80n = 6800

n = 6800/80

n = 85

jek_recluse [69]3 years ago
5 0
The answer would be n = 85.

4/5 = 68/n

4/5n = 68

4n/5 = 68

4n = 68 * 5

4n = 340

n = 340/4

n = 85.
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KonstantinChe [14]
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Carry the 2 over to the 3 behind the 4 and multiply so 2times2 is 4. So i new equation is.
X^2+4x+4
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8 0
3 years ago
Question 1
Ivenika [448]

Answer:

66.125

Step-by-step explanation:

5 0
3 years ago
Solve for x: x - 7 = -10<br><br> A.17<br> B. 3<br> C. -17<br> D. -3
ratelena [41]
B(3) because 3-7=-10
6 0
3 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
In circle O, the radius is 4, and the length of minor arc AB is 4.2 feet. Find the measure of minor arc AB to the nearest degree
Degger [83]

The formula for arc length is s=r*angle theta where s is the arc length, r is the radius, and angle theta is central angle formed by the arc in radians.

In this case, the angle would be s/r or 4.2/4  which is 1.05 radians. We have to convert this into degrees and so you would multiply 1.05 by (180/pi) which results in approximately 60 degrees. Remember, if you want to convert radians into degrees, the conversion factor is 180/pi and for degrees into radians, it is pi/180.

4 0
3 years ago
Read 2 more answers
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