Your answer is incorrect. Suppose that a "code" consists of 6 digits, none of which is repeated. (A digit is one of the 10 numbe
rs 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 .) How many codes are possible?
2 answers:
Use factorials to solve this problem.
When you are choosing a number of digits from a set without repetition, you will use the following formula:

n represents the total amount of items in the set, and r represents the number of items you will take out.
There are 10 digits, and you are choosing sets of 6 digits for your code. Plug the values into the equation:


There are
151,200 different 6-digit codes possible.
Take me the brayniest.i hope it was helpful
You might be interested in
Answer:
(9 + r)/6
Step-by-step explanation:
Answer:
I know brainly is not the place to go for math
Step-by-step explanation:
Answer:
it is at -2 degrees
Step-by-step explanation:
sorry for being late but if anyone in the future sees this hears the answer!
have a good one!
Q + d = 16....q = 16 - d
0.25q + 0.10d = 3.10
0.25(16 - d) + 0.10d = 3.10
4 - 0.25d + 0.10d = 3.10
-0.25d + 0.10d = 3.10 - 4
-0.15d = -0.90
d = -0.90/-0.15
d = 6...dimes
q + d = 16
q + 6 = 16
q = 16 - 6
q = 10...quarters
so there are (10 - 6) = 4 more quarters then dimes
I’m not sure but i really really really like points!!!!