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NARA [144]
3 years ago
14

How many solutions are there in this equation 8 (x-3)=8x-24

Mathematics
2 answers:
MatroZZZ [7]3 years ago
4 0
It should be all real numbers, because if you plug in lets say a 1 that would be 8(1-3) = 8(1) -24  or a 2 that would be 8(2-3)= 8(2) -24
     8(-2) = 8 -24                                          8(-1) = 16 -24
      -16  = -16                                               -8    =    -8
kari74 [83]3 years ago
3 0
Performing the indicated multiplication on the left side gives you:

8x-24=8x-24,

8x=8x

1=1 

These expressions are true for any real value of x and thus has infinitely many solutions...
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What would be the function for this?
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3 years ago
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
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Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

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The number of combinations for each of these is given by the product between the number of students in the club, so we get:

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For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

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