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strojnjashka [21]
3 years ago
14

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent

ed by the shaded​ region?

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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toni bought an old bike for 50$. She fixed it up and sold it for $80. What percent of the original value was toni’s sale price
ikadub [295]
For this case what you must do is the following rule of three:
 50 ---> 100
 80 ----> x
 We clear x:
 x = (80/50) * (100)
 x = 160%
 160-100 = 60%
 Answer:
 toni added 60% of the original value for his sale price
3 0
3 years ago
Paula and Kawai shared $312 in the ratio of 6:7. How much money<br> did each person get?
Maslowich

Answer:

Paula get \$144 and Kawai get \$168.

Step-by-step explanation:

Given: Paula and Kawai shared \$312 in the ratio of 6:7.

To find: How much money  did each person get?

Solution:

We have,

Paula and Kawai shared \$312 in the ratio of 6:7.

So, let Paula get \$6x and Kawai get \$7x.

As per the question,

6x+7x=312

\implies13x=312

\implies x=\frac{312}{13} =24

Therefore, Paula get 6\times 24=\$144, and Kawai get 7\times 24=\$168.

Hence, Paula get \$144 and Kawai get \$168.

6 0
3 years ago
The area of a parallelogram is 20 square miles find its base and height
timama [110]

Answer:

refer to explanation

Step-by-step explanation:

the lengths of the base and height are the factors of 20

so they can be 5×4, 10×2, 1×20

3 0
2 years ago
Vivian found data about her city's population and made a scatter plot the equation of the linebbest fit for. Her data is p= 637.
Andre45 [30]

Answer:

annual growth rate m = 637.5 people / year

Step-by-step explanation:

Solution:-

- The scatter plot displaying the city's population was modeled by a linear equation of the form:

                               y = m*x + c

Where, m and c are constants.

- The scatter plot displayed the following relation of the city's population (p):

                               p = 637.5*t + 198,368.1

Where, p : The population in t years after after 1990

            t : The number of years passed since 1990.

- The slope of the graph "m = 637.5" denotes the rate of change of dependent variable with respect ot independent variable:

                             dp / dt = m = 637.5

- So the rate of change of population per unit time t since 1990 has been constant with a an annual growth rate m = 637.5 people / year

7 0
3 years ago
When people make estimates, they are influenced by anchors to their estimates. A study was conducted in which students were aske
12345 [234]

Answer:

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

where μ1: mean calorie estimation for the cheesecake group and μ2: mean calorie estimation for the organic salad group.

There is enough evidence to support the claim that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first (P-value=0.0000002).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Suppose that the study was based on a sample of 20 people who thought about the cheesecake first and 20 people who thought about the organic fruit salad first, and the standard deviation of the number of calories in the cheeseburger was 128 for the people who thought about the cheesecake first and 140 for the people who thought about the organic fruit salad first.</em>

<em>At the 0.01 level of significance, is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first?"</em>

<em />

This is a hypothesis test for the difference between populations means.

The claim is that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

The significance level is 0.01.

The sample 1 (cheese cake), of size n1=20 has a mean of 780 and a standard deviation of 128.

The sample 2 (organic salad), of size n2=20 has a mean of 1041 and a standard deviation of 140.

The difference between sample means is Md=-261.

M_d=M_1-M_2=780-1041=-261

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{128^2}{20}+\dfrac{140^2}{20}}\\\\\\s_{M_d}=\sqrt{819.2+980}=\sqrt{1799.2}=42.417

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-261-0}{42.417}=\dfrac{-261}{42.417}=-6.153

The degrees of freedom for this test are:

df=n_1+n_2-1=20+20-2=38

This test is a left-tailed test, with 38 degrees of freedom and t=-6.153, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.0000002) is smaller than the significance level (0.01), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.

3 0
3 years ago
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