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Rainbow [258]
3 years ago
15

Angles ∝ and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of ∝

if ∝ < β.
Mathematics
1 answer:
snow_lady [41]3 years ago
8 0
<span><span>Well, since we know that sin(x) = cos(90-x), we can transform the given into
2x - 8/3 = 90 - (4x - 10/3)
2x - 8/3 = 90 - 4x + 10/3
Now clear fractions by multiplying by three...

6x - 8 = 270 - 12x + 10
6x - 8 = 280 - 12x
18x = 288
x = 16
4x - 10/3 = 4(16) - 10/3 = 64 - 3.33 = 60.67 degrees.
Choice C.</span><span>
</span></span>
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Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,
mario62 [17]

Answer:

The equation of the ellipse is \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where

  • The coordinates of the vertices are (± a , 0)  
  • The coordinates of the foci are (± c , 0) , where c ² = a² - b²  

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √  for both sides

∴ b = ± 15

∵ The equation of the ellipse is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

- Substitute the values of a and b in it

∴ \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1 ⇒ \frac{x^{2}}{289}+\frac{y^{2}}{225}=1  

∴ The equation of the ellipse is \frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1

6 0
3 years ago
A swimming pool is draining at a constant rate. The table shows the proportional relationship between the change in the water le
kaheart [24]

Answer:

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second:-15.75

third:-40.25

Step-by-step explanation:i am too lazy srry

6 0
3 years ago
At a certain college, the ratio of men to women is 6 to 5. If there are 1,500 men, how many women are there?
Fed [463]

Let 6x represent the men

5x represents the women

The ratio of men to women is 6 to 5 or 6/5


6x / 5x = 1500/ W  where W is the number of women

6/5 = 1500/W

W =  1250 women


4 0
4 years ago
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