What is the slope of a line perpendicular to the line whose equation is 2x+4y=-642x+4y=−64. Fully simplify your answer.

Mathematics

1 answer:

labwork [276]3 years ago

5 0

9514 1404 393

Answer:

Step-by-step explanation:

Solving the given equation for y, you have ...

2x +4y = -64

4y = -2x -64

y = -1/2x -16

The coefficient of x is the slope of the given line: -1/2. The slope of the perpendicular line is the opposite reciprocal of this:

-1/(-1/2) = 2

The slope of the perpendicular line is 2.

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Plz help me Find LM.

Ira Lisetskai [31]

Because LP and NP are the same measure, that means that MP is a bisector. It bisects side LN and it also bisects angle LMN. Where MP meets LN creates right angles. What we have then thus far is that angle LMP is congruent to angle NMP and that angle LPM is congruent to angle NPM and of course MP is congruent to itself by the reflexive property. Therefore, triangle LPM is congruent to triangle NMP and side LM is congruent to side NM by CPCTC. Side LM measures 11.

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2 years ago

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Thepotemich [5.8K]

Answer:

The solution is B

Step-by-step explanation:

$x + 5 \geqslant 1 \\ x \geqslant 1 - 5 \\ x \geqslant - 4$