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3 years ago

Pls help !!!!!!!!! i need help fast !!!!

Mathematics

1 answer:

Zepler [3.9K]3 years ago

7 0

9514 1404 393

Answer:

the product is equal to 409
the product is less than 751
the product is less than 173

Step-by-step explanation:

A fraction has a numerator (above the fraction bar) and denominator (below the fraction bar). The denominator tells you the number of equal pieces one whole is divided into. The numerator tells you how many of those pieces you have.

If you have fewer than the total number of pieces, you have less than the whole amount.

If the numerator and denominator are equal, you have exactly the whole amount.

If the numerator is larger than the denominator, you have more than the whole amount.

The first fraction, 72/72 is equal to 1. Multiplying by that value gives the original number. The product is equal to 409.

The second and third fractions have numerators less than their denominator. They represent less than the whole amount, so multiplying by those values will give a product less than the original number:

less than 751

less than 173

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Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

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3 years ago

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Answer:

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Step-by-step explanation:

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