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forsale [732]
3 years ago
8

Help, I need to pass this class

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0
45/9 is 5 it means 1 part is =5 
 and  5 *  5 is = 25
32 - 25 = 7 

its b

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4a − 3 = 9 + a..........................
OverLord2011 [107]

Answer:

4a - 3 = 9 + a \\ 4a  - a = 9 + 3 \\ 3a = 12 \\ a  = \frac{ 12}{3}  \\ a = 4

I hope this help

7 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Sergio039 [100]

Answer:

sqrt41

Step-by-step explanation:

a^2+b^2=c^2

25+16=41

sqrt41

8 0
3 years ago
Read 2 more answers
Colin is working to earn some money for a new CD player. On Saturday he earns half as much as he did on Sunday, but twice as muc
Marysya12 [62]

Answer:

Friday=$10 Saturday=$20 Sunday=$40

Step-by-step explanation:

On Friday we can estimate that he earnt $10 so twice as many as that is $20 so on Saturday he could of earnt that much. Finally what is 20 half of? 40 so 10+20+40=$70

3 0
3 years ago
What do you add to 17/4 to make 5?
marusya05 [52]

Answer:

3/4 is what you are adding

17/4+3/4=20/4=5

3 0
2 years ago
Read 2 more answers
Help,anyone can help me do quetion.​
3241004551 [841]

Answer:

(a) x = 128^{o}

(b) x = 74^{o}

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

                        = 3 x 180

                        = 540^{o}

Thus,

x + 90 + 76 + 110 + 136 = 540^{o}

x + 412 = 540^{o}

x = 540^{o} - 412

x = 128^{o}

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

  = 142^{o}

y = 142^{o}

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = 540^{o}

z + 434 = 540^{o}

z = 540^{o} - 434

  = 106^{o}

z = 106^{o}

But, x + z = 180^{o}

Then;

x + 106^{o} = 180^{o}

x = 180^{o} - 106^{o}

  = 74^{o}

x = 74^{o}

7 0
3 years ago
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