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zubka84 [21]
3 years ago
10

Solve the equation.

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0
(x+4)(x+6)=0
x = -4, x=-6

The answer is C.
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In a school annual day function a variety programme was organised. It was planned that
Over [174]

Answer:

(a) 65318400

(b) 1080

(c) 311040

Step-by-step explanation:

I think you forgot to put the questions

(a) if the programmes can be perfomed in any order ?

(b) if the programmes of the same kind were perfomed at a stretch?

(c) if the programmes of the same kind were perfomed at a strech and considering the order of performance of the programmes of the same kind?

if you need the step by step solutions, visit

https://brainly.in/textbook-solutions/q-20-school-annual-day-function-variety-programme-3#q-20-school-annual-day-function-variety-programme-2

4 0
2 years ago
Identify the zeros of f(x) = (x + 9)(x − 4)(6x + 1).
slavikrds [6]
<h2>The required 'option a)  - 9 , \dfrac{-1}{6}, 4' is correct.</h2>

Step-by-step explanation:

We have,

f(x) = (x + 9)(x − 4)(6x + 1)

To find, all zeroes of the given equation = ?

∴ f(x) = (x + 9)(x − 4)(6x + 1)

⇒ (x + 9)(x − 4)(6x + 1) = 0

⇒ x + 9 = 0 or, x − 4 = 0 or, 6x + 1 = 0

⇒ x + 9 = 0 ⇒  x = - 9

⇒ x − 4 = 0 ⇒ x = 4

⇒ 6x + 1 = 0

⇒ 6x = - 1

⇒ x = \dfrac{-1}{6}

∴ x = - 9 , \dfrac{-1}{6}, 4

Thus, the required 'option a)  - 9 , \dfrac{-1}{6}, 4' is correct.

3 0
3 years ago
Read 2 more answers
A football stadium holds 52,000 fans. A college student is doing research and determines that on any given game day, the home te
docker41 [41]
This problem is asking us to make an algebraic equation or representation of the situation. First we have to assign the variables which is already given in the problem. H is the number of the home team and V is the visiting team. Since the problem states there are the home team has five times as manyfans as the visiting team, then it can be represented as: 

H = 5V
Also, H + V = 52,000. H and V can then be solves by solving the 2 equations simultaneously. The results are 43,333 and 8,667. 
4 0
3 years ago
A certain lot consisting of ten items has three defective items and seven nondefective items. How many possible subsets of 2 ite
Charra [1.4K]

Answer:

45

Step-by-step explanation:

The order in which the items are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many possible subsets of 2 items can be chosen from this lot?

Combinations of 2 from a set of 10. So

C_{10,2} = \frac{10!}{2!(10-2)!} = 45

4 0
2 years ago
14 lessons costs $210. What would 72 lessons cost
Oksi-84 [34.3K]

Answer:

$1,080

Step-by-step explanation:

To solve, we can make a proportion

14 lessons are $210 and 72 lessons are $x

14/210=72/x

Cross multiply

14*x=210*72

14x=15120

To solve for x, we need to get x by itself. Since x is being multiplied by 14, divide both sides by 14.

14x/14=15120/14

x=1080

So, 72 lessons will cost $1,080

4 0
2 years ago
Read 2 more answers
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