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3 years ago

Solve the equation.

Mathematics

1 answer:

Hitman42 [59]3 years ago

4 0

(x+4)(x+6)=0
x = -4, x=-6

The answer is C.

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What is the average speed between 2 seconds and 8 seconds.

Gennadij [26K]

Add the two speeds together, then divide the two, this gives the average speed. Hope this was helpful!

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3 years ago

Read 2 more answers

Find the length of the arc and express your answer as a fraction times pie

Elina [12.6K]

Solution:

Given a circle of center, A with radius, r (AB) = 6 units

Where, the area, A, of the shaded sector, ABC, is 9π

To find the length of the arc, firstly we will find the measure of the angle subtended by the sector.

To find the area, A, of a sector, the formula is

$\begin{gathered} A=\frac{\theta}{360\degree}\times\pi r^2 \\ Where\text{ r}=AB=6\text{ units} \\ A=9\pi\text{ square units} \end{gathered}$

Substitute the values of the variables into the formula above to find the angle, θ, subtended by the sector.

$\begin{gathered} 9\pi=\frac{\theta}{360\degree}\times\pi\times6^2 \\ Crossmultiply \\ 9\pi\times360=36\pi\times\theta \\ 3240\pi=36\pi\theta \\ Divide\text{ both sides by 36}\pi \\ \frac{3240\pi}{36\pi}=\frac{36\pi\theta}{36\pi} \\ 90\degree=\theta \\ \theta=90\degree \end{gathered}$

To find the length of the arc, s, the formula is

$\begin{gathered} s=\frac{\theta}{360\degree}\times2\pi r \\ Where \\ \theta=90\degree \\ r=6\text{ units} \end{gathered}$

Substitute the variables into the formula to find the length of an arc, s above

$\begin{gathered} s=\frac{\theta}{360}\times2\pi r \\ s=\frac{90\degree}{360\degree}\times2\times\pi\times6 \\ s=\frac{12\pi}{4}=3\pi\text{ units} \\ s=3\pi\text{ units} \end{gathered}$

Hence, the length of the arc, s, is 3π units.

4 0

1 year ago

The Kuroshio Sea tank is 27m long, 35m wide and 10m deep. What is the volume of the tank? Show your

umka21 [38]

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

Step-by-step explanation:

The given is,

Kuroshio Sea tank is 27m long, 35m wide and 10m deep.

Step:1

Sea tank looks like a rectangular prism,

Formula to calculate the volume of rectangular prism,

$Volume, V =whl$ .............................(1)

Where, w - Width of the rectangular prism

h - Height or depth of the rectangular prism

l - Length of the rectangular prism

From given,

w = 35 meters

l = 27 meters

h = 10 meters

Equation (1) becomes,

$V = (35)(10)(27)$

$= (945)(10)$

$=9450$

Volume of the sea tank, V = 9450 Cubic meters

Result:

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

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3 years ago

Complete the function using the function y=-2x -6<br> -2<br> 0<br> 2<br> 4

Mariana [72]

I need more info please!!

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3 years ago

What is the solution set of the compound inequality 3.5x - 10> -3 and 8x -9 <39

Eva8 [605]

I need to answer two questions in order to ask a question. sorry that i’m stupid and have no idea how to do this

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3 years ago