*sigh* 9,000,000.00 +30,000.00 +2,000.00+ 500.00 + 4.00 + 0.70 + 0.05.
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
3x/8 divided by 7y/4
you can not divide fractions, so you must multiply by the reciprocal.
3x/8 x 4/7y now you can simplify the 4 and 8
3x/2 x 1/7y now multiply across
3x/2(7y)
3x/14y should be your answer
6 is the answer I believe
Answer:
Conversion rates US Dollar / Mexican Peso
10 USD 209.37500 MXN
20 USD 418.75000 MXN
50 USD 1046.87500 MXN
100 USD 2093.75000 MXN
