Answer is: <span>the mass of the glucose is 81,07 grams.
</span>c(C₆H₁₂O₆) = 0,3 M = 0,3 mol/L.
V(C₆H₁₂O₆) = 1,500 L.
n(C₆H₁₂O₆) = c(C₆H₁₂O₆) · V(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 0,3 mol/L · 1,5 L.
n(C₆H₁₂O₆) = 0,45 mol.
m(C₆H₁₂O₆) = n(C₆H₁₂O₆) · M(C₆H₁₂O₆).
m(C₆H₁₂O₆) = 0,45 mol · 180,156 g/mol.
m(C₆H₁₂O₆) = 81,07 g.
Hopefully this will help you my friend.
To solve this problem, we must be given first the density
of air at 20 degrees Celsius. Looking up online, this is equal to:
density air (20C) = 0.0012041 g/mL
so that the volume is:
volume balloon = 0.57 g / (0.0012041
g/mL)
<span>volume balloon = 473.38 mL</span>
The distance light travels in 1 second - <span>186,282 miles
Therefore distance it takes to travel within 182 seconds - </span><span>186,282 miles/second x 182 seconds
Therefore to find the answer we need to </span>multiply the distance it travels within a second with the amount of seconds it takes
correct answer is A) <span>186,282 ⋅ 182</span>
