Question

Determine the number of moles of water produced when one mole of NH3 reacts according to the balanced reaction shown. 4 NH3 + 5 O2 → 4 NO + 6 H2O

Answer 1

Answer : The number of moles of water produced are, 1.5 moles

Explanation : Given,

Moles of $NH_3$ = 1 mole

The given balanced chemical reaction is,

$4NH_4+5O_2\rightarrow 4NO+6H_2O$

By the stoichiometry we can say that, 4 moles of ammonia gas react with 5 moles of oxygen gas to produce 4 moles of nitric oxide and 6 moles of water as a product.

As, 4 moles of ammonia react to give 6 moles of water

So, 1 moles of ammonia react to give $\frac{6}{4}=1.5$ moles of water

Therefore, the number of moles of water produced are, 1.5 moles

Answer 2

1.5 moles of water

Further explanation

Given:

One mole of NH₃

Question:

Determine the number of moles of water produced.

The Process:

A balanced reaction is shown as follows:  

$\boxed{ \ 4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O \ }$

Ammonia gas reacts with oxygen to produce nitrogen monoxide and water. The reaction has been balanced. The ratio of the number of coefficients represents the number of moles of each substance.

Mole ratio: $\boxed{ \ NH_3 : O_2 : NO : H_2O = 4 : 5 : 4 : 6 \ }$

From the balanced reaction above, it can be said that 4 moles of NH₃ (or ammonia) that react will produce 6 moles of H₂O (or water).

Let us find out the number of moles of water produced from one mole of NH₃.

$\boxed{ \ \frac{mole \ of \ H_2O}{mole \ of \ NH_3} = \frac{6}{4}\ }$

Simplify $\boxed{\frac{6}{4} \rightarrow \frac{3}{2}}$

$\boxed{ \ mole \ of \ H_2O = \frac{3}{2} \times mole \ of \ NH_3 \ }$

$\boxed{ \ mole \ of \ H_2O = \frac{3}{2} \times 1 \ mol \ NH_3 \ }$

Thus the number of moles of water produced is equal to ³/₂ moles (or 1.5 moles).

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Notes:

The stoichiometric calculation is a calculation in which chemical equations and the coefficients are used to calculate the amount of one substance from a second one.  

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