Answer: the line Spectra of hydrogen lies between the ultra-violet, visible light and infra-red of the electro magnetic spectrum
Explanation:
Electromagnetic radiation spans an wide range of wavelengths and frequencies. This range is called the electromagnetic spectrum. The electromagnetic spectrum is generally divided into seven regions, in order of decreasing wavelength and increasing energy and frequency. The 7 regions includes; radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV), X-rays and gamma rays.
lower-energy radiation, such as radio waves, is expressed as frequency while microwaves, infrared, visible and UV light are usually expressed as wavelength and finally, higher-energy radiation such as X-rays and gamma rays, is expressed in terms of energy per photon.
Therefore, hydrogen lies between the ultra-violet, visible light and infra-red region of the electro magnetic spectrum.
Answer:
The net ionic equation is as follows:
HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)
Explanation:
The reaction between Hydrocyanic acid, HCN, and sodium hydroxide is a neutralization reaction between a weak acid and a strong base.
Hydrocyanic acid being a weak acid ionizes only slightly, while sodium hydroxide being a strong base ionizes completely. The equation for the reaction is given below:
A. HCN(aq) + NaOH-(aq) ----> NaCN(aq) + H2O(l)
Since Hydrocyanic acid is written in the aqueous form as it ionizes only slightly and the ionic equation is given below:
HCN(aq) + Na+(aq)+OH-(aq) ----> Na+(aq)+CN-(aq) + H2O(l)
Na+ being a spectator ion is removed from the net ionic equation given below:
HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)
Answer:
Explanation:
alright, dawg, lets get this bread. CHEMISTRY? OH YEAH I LOVE CHEMISTRY.
what is a mol? do you know who avogadro is? sounds like avocado. free shavocado. ok so you MUST REMEMBER THIS NUMBER PLEASE.
please remember this number and commit it to your memory: avogadros number
this is how much a mole is. you know how a pair is 2 and a dozen is 12? ok so a mole is it is confusing at first but hopefully this helps you to understand.
now that we understand this..... lets perform this calculation with a calculator
notice i divide the question by the avogadros number to find out how many moles are in the number. ok but listen... it gets into a tough area here... because HOW ARE WE TO DIVIDE SUCH A HUMONGOUS NUMBER BY ANOTHER HUMONGOUS NUMBER?!?!?
its easy, its cake, just listen this is how you do it. only focus on the numbers NOT the 10 exponential ones. so just 3.90 and 6.02 ok? lets divide these two numbers 3.90 / 6.02 and we get 0.6478... how interesting... ok now lets deal with the exponents of 10. notice that we are DIVIDING these numbers so think of it as subtracting the exponents of ten..... 22 minus 23 equals -1
so we have 
now this negative 1 thing is annoying so lets just make it to the power of 0
and anything to the power of 0 just becomes 1.
0.06478
so this is our answer but keep in mind we need 3 sig figs. if we round then we get 0.0648
put this into scientific notation we get
Answer:
By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.
Explanation:
An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.
Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.
Answer:
The specific heat of the alloy is 2.324 J/g°C
Explanation:
<u>Step 1:</u> Data given
Mass of water = 0.3 kg = 300 grams
Temperature of water = 20°C
Mass of alloy = 0.090 kg
Initial temperature of alloy = 55 °C
The final temperature = 25°C
The specific heat of water = 4.184 J/g°C
<u>Step 2:</u> Calculate the specific heat of alloy
Qlost = -Qwater
Qmetal = -Qwater
Q = m*c*ΔT
m(alloy) * c(alloy) * ΔT(alloy) = -m(water)*c(water)*ΔT(water)
⇒ mass of alloy = 90 grams
⇒ c(alloy) = the specific heat of alloy = TO BE DETERMINED
⇒ ΔT(alloy) = The change of temperature = T2 - T1 = 25-55 = -30°C
⇒ mass of water = 300 grams
⇒ c(water) = the specific heat of water = 4.184 J/g°C
⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C
90 * c(alloy) * -30°C = -300 * 4.184 J/g°C * 5°C
c(alloy) = 2.324 J/g°C
The specific heat of the alloy is 2.324 J/g°C
