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3 years ago

: calculate the mass of the solute in 1.500 l of 0.30 m glucose, c6h12o6, used for intravenous injection

1 answer:

8 0

Answer is: the mass of the glucose is 81,07 grams.
c(C₆H₁₂O₆) = 0,3 M = 0,3 mol/L.
V(C₆H₁₂O₆) = 1,500 L.
n(C₆H₁₂O₆) = c(C₆H₁₂O₆) · V(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 0,3 mol/L · 1,5 L.
n(C₆H₁₂O₆) = 0,45 mol.
m(C₆H₁₂O₆) = n(C₆H₁₂O₆) · M(C₆H₁₂O₆).
m(C₆H₁₂O₆) = 0,45 mol · 180,156 g/mol.
m(C₆H₁₂O₆) = 81,07 g.

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Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

2 years ago

How much of a chemical should you take?

barxatty [35]

Answer:

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2 years ago

What claim is being made?

dangina [55]

The correct answer is c

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3 years ago

Read 2 more answers

Una muestra de 1 gramo de un elemento contiene 1,5 x 1022 atomos, cual es su masa molar❓❓

marusya05 [52]

El número de Avogadro es 6,022 x 10^23, y es el número de átomos que hay en un mol de dicho elemento. A su vez un mol es la cantidad de un elemento cuya masa en gramos coincide con el peso atómico.

Por tanto, 6,022 x 10^23 átomos del elemento tienen una masa en gramos igual a su peso atómico. Hacemos una regla de tres:

1 gramo -------- 1,5 x 10^22 átomos

x ------------------ 6,022 x 10^23 átomos

=> x = 40,1 gramos por mol del elemento.

De modo que su peso atómico es 40,1. Se trata del calcio.

Saludos.

7 0

3 years ago

N methyl 2 pyrrolidone heated with aqueous acid reaction

monitta

N-methyl 2 pyrrolidone is a cyclic amide and it when heated with aqueous acid gives the product as a cyclic amino acid. The product name is N-Methyl-4-aminobutyric acid

The reaction is given as follows in the attached picture.

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