Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
Answer:
1471.15
Step-by-step explanation:
See attached picture for solution:
x-0.1x=36
where x is the original price
0.1x is the discount (10% of the original price)
36 is the price paid
x-0.1x=36
0.9x=36
----- ----
0.9 0.9
x=40
The original price is $40.00
To find the number of red bricks used, you can create a part to part to whole ratio from the simple ratio of red to grey brick they give.
Then, use the total to create an equivalent ratio with the actual total number of bricks (140).
<u>5 red </u> <u>100 red</u>
<u>2 grey</u> = <u>40 grey</u>
7 total 140 total
<u>
</u>Each time, the simple ratio was multiplied by 20 to get the actual totals for each color.
<u>
</u>There were 100 red bricks used.<u>
</u>