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Gnoma [55]
3 years ago
7

There is a great danger for thunderstorms when there are ________ clouds in the sky. (4 points) Select one: a. stratus b. cirrus

c. few d. cumulus
Physics
1 answer:
aksik [14]3 years ago
3 0

The answer is a.) stratus

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Two objects must be in contact for them to exert a force on each other. <br><br> True<br> False
Irina-Kira [14]

Answer:

False

Explanation:

The given statement "Two objects must be in contact for them to exert a force on each other" is not true as there are many types of forces that doesn't require being in contact for exerting a force.

One such example is the gravitational force acting between two bodies. Gravitational force is the force of pull with which a body pulls another body without being in contact.

For two bodies of masses 'M' and 'm' separated at a distance of 'R', the gravitational force is given as:

Force=\frac{GMm}{R^2}\\Where,G\to \textrm{Universal Gravitational constant}

The gravitational force acts always act between bodies that have mass. The bodies are not in contact yet experience force.

Therefore, the given statement is false.

5 0
4 years ago
What is the frequency of a wave that has a wavelength of 3m that is traveling at a speed of 9m/s
dezoksy [38]

Answer:

3 m/s

Explanation:

4 0
3 years ago
A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is 1 .With her
kow [346]

Correct question is;

A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is I. With her arms folded,the moment of inertia about the same axis becomes 0.6I about the same axis. Calculate the new rate of spin.

Answer:

4 rev/s

Explanation:

We are given;

Initial Angular velocity; ω_i = 2.4 rev/s

Initial moment of inertia; I_i = I

Final moment of inertia; I_f = 0.6I

From conservation of angular momentum, we have;

I_i × ω_i = I_f × ω_f

Where ω_f is the new rate of spin.

Thus, let's make it the subject to get;

ω_f = (I_i × ω_i/I_f)

Plugging in relevant values, we have;

ω_f = (I × 2.4/0.6I)

I will cancel out to give;

ω_f = 2.4/0.6

ω_f = 4 rev/s

5 0
3 years ago
Find the acceleration of a box of mass 3.0 kg, if applied force is 20.0 N at 37° above the x axis, and the coefficient of kineti
ExtremeBDS [4]

Hello:

First, <u>the normal force</u> in y axis:

∑Fy = 0

∑Fy = N - Fy

∑Fy = N - 20 N * sen 37°

∑Fy = N = 12,87 N

Formula:

R = ma

F - F' = ma

F - (μN) = ma

20 N - (0.2 * 12,87 N) = 3 kg * a

20 N - 2.574 N = 3 kg * a

17,426 N / 3 kg = a

a = 5,8 m/s²

4 0
3 years ago
Calculate the mass of an asteroid moving at 500 m/s moving with 125,000 kgm/s of momentum.
soldi70 [24.7K]

Answer:

M = 250kg

Explanation:

Ft = M x V

Where ft = momentum

M = mass

V = velocity

Given

Ft = 125,000 kgm/s

V = 500m/s

Therefore

125000 = M x 500

Divide both sides by 500

125000/500 = M x 500/500

250 = M

M = 250kg

4 0
3 years ago
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