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3 years ago

Why cant people with aids foght out the infection?

2 answers:

6 0

Because aids is a power disease, u can get it from anything but commonly its through sexual intercourse or oral and most people who get it CANT fight it because it has already reached their blood stream with the disease of aids. Aids CANT be cured purely but can be TREATED through special procedures depending on HOW u got aids in the first place. It can even be kissing another person who may be sick or already has aids and just transferred it to u.

Hope this helps.

sveta [45]3 years ago

3 0

They can fight the infection but not the disease

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What is the weight of the body under the influence of a force of 10N reaches a speed of 1.5 m / s in 3s?

MariettaO [177]

Answer:

Explanation:

F=ma

F=10N

A=v-u upon t

=1.5-0 upon 3

=0.5m per second squared

Then do force divided by. Accelaration and multiply by gravity.

8 0

2 years ago

Which question should Trudy write

Tanzania [10]

A real question, one with a question mark?

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3 years ago

Un cuerpo se mueve, partiendo del reposo, con una aceleración constante de 8 m/s². Calcular la velocidad que tiene al cabo de 5s

nataly862011 [7]

Answer:

v = 40 m / s

Explanation:

Let's use the expressions for accelerated motion

v = v₀ + a t

where vo is the initial velocity, at the acceleration and t is the time.

as the body starts from rest its initial velocity is zero

v = 0 + at

let's calculate

v = 8 5

v = 40 m / s

8 0

2 years ago

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b

Mnenie [13.5K]

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

$Q=t^3-2t^2+4t+4$

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

$I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4$

At t = 1 s,

Current,

$I=3(1)^2-4(1)+4\\\\I=3\ A$

So, the current at t = 1 s is 3 A.

For lowest current,

$\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s$

Hence, this is the required solution.

7 0

3 years ago

Why does the density of a substance remain the same for different amounts of the substance

Novay_Z [31]

The molarity remains the same so the ratio does not change

5 0

3 years ago