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2 years ago

Why cant people with aids foght out the infection?

2 answers:

6 0

Because aids is a power disease, u can get it from anything but commonly its through sexual intercourse or oral and most people who get it CANT fight it because it has already reached their blood stream with the disease of aids. Aids CANT be cured purely but can be TREATED through special procedures depending on HOW u got aids in the first place. It can even be kissing another person who may be sick or already has aids and just transferred it to u.

Hope this helps.

sveta [45]2 years ago

3 0

They can fight the infection but not the disease

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. Calculate the efficiency of a bicycle if the input work to turn the pedal is 45J and the output work is 20J. * 1 point 2.25 2.

cestrela7 [59]

20/45=0.4*100= 44.4 so the answer is..................................................

Answer: 44.4%

8 0

3 years ago

A convex lens of focal length 35 cm produces a magnified image 2.5 times the size of the object. What is the object distance if

Zanzabum

Answer:

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

Explanation:

u = Object distance

v = Image distance

f = Focal length = 35

m = Magnification = 2.5

$m=-\frac{v}{u}\\\Rightarrow 2.5=-\frac{v}{u}\\\Rightarrow v=-2.5 u$

Lens equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{35}=\frac{1}{u}+\frac{1}{-2.5u}\\\Rightarrow \frac{1}{35}=\frac{3}{5u}\\\Rightarrow u=21\ cm$

$v=-2.5\times 21=-52.5\ cm$

Image distance is -52.5 cm

Image is virtual and forms on the same side of the lens and upright image is formed.

3 0

2 years ago

6. A ball rolled 125 m from the top of a hill to the bottom of a hill. How long

leva [86]

Time = distance / speed
T = 125/ 5
T = 25 meters per second

7 0

2 years ago

water has an index of refraction of 1.33. What is the critical angle for light leaving a pool of water into air? 0 37 90 49

vesna_86 [32]

When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.

The value of the critical angle is given by:
$\theta = \arcsin ( \frac{n_2}{n_1} )$
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
$\theta = \arcsin ( \frac{1.00}{1.33} )=49^{\circ}$

6 0

3 years ago

I need help plz and thank you this is do

love history [14]

Answer:

Oh I am sorry this is my first time on brainly i dont how to exit and sorry but dont know the answer

Explanation:

4 0

2 years ago