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Lilit [14]
3 years ago
12

If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that th

e person would need to see an object at infinity clearly?
If a farsighted person has a near point that is 0.600m from the eye, what is the focal length f2 of the contact lenses that the person would need to be able to read a book held at 0.350m from the person's eyes?

Physics
1 answer:
olga55 [171]3 years ago
3 0

Answer:

f1= -350cm or -3.5m

f2= 22.1cm or 0.221m

Explanation:

A person is nearsighted when the person's far point is less than infinity. A diverging lens is normally used to correct this eye defect. A diverging lens has a negative focal length as seen in the solution attached.

Farsightedness is when a person's near point is farther than 25cm. This eye defect is corrected using a converging lens. The focal length of a converging lens is positive. This is evident in the solution attached. The near point is also referred to as the least distance of distinct vision.

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<h3>Answer:</h3>

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<h3>Explanation:</h3>

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8 0
3 years ago
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A 259-kV power transmission line carrying 429 A is hung from grounded metal towers by ceramic insulators, each having a 0.71×109
ella [17]

Answer:

The resistance is 7.47\times10^{6}\ \Omega.

Explanation:

Given that,

Power = 259 kV

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Resistance R=0.71\times10^{9}\ Omega

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I=\dfrac{P}{R}

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I=\dfrac{259\times10^{3}}{0.71\times10^{9}}

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\dfrac{1}{R}=\dfrac{95}{0.71\times10^{9}}

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8 0
3 years ago
A spring requires 10 N of force to hold it 1 m past its natural length. How much work is required to stretch it from its natural
Ulleksa [173]

Answer:

5 J

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Spring force is given as

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k = 10 N/m

W = work done in stretching the spring

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W = (0.5)k x²

Inserting the values

W =  (0.5) (10) (1)²

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4 years ago
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