Answer:
The length of the hypotenuse is 2.4m
Step-by-step explanation:
well to start we have to know the relationship between angles, legs and the hypotenuse
α = 55°
o: opposite = 2.0m
h: hypotenuse
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, hypotenuse, opposite)
we look at which meets those data between the sine, cosine and tangent
is the sine
sin α = o/ah
Now we replace the values and solve
sin 55 = 2.0/h
0.81915 = 2.0/h
h = 2.0 / 0.81915
h = 2.4415 m
round to the nearest tenth
h = 2.4415 = 2.4 m
The length of the hypotenuse is 2.4m
Step-by-step explanation:
- h²=p²+b²
- h²=24²+7²
- h²=576+49
- h=√625
- h=25
tanA=p/h
its yr ans
hope it helps.
<h2>stay safe healthy and happy....</h2>
I'm doing 3
For 3, using a table is very similar to a double number because the numbers are matching up in both ways.
On the bottom of a double number line we have like, for example,-- the bottom of the double number line would have batches. And its 1, 2, 3 ,4 , etc.
And on a table, it would be the same, the numbers on both diagrams have the same methods, have same way of lining things up but they're just drawn differently.
Hope this helped!
Answer:
Ball Bearing Volume = (4 / 3) * PI * radius ^3
Volume = (4 / 3) * 3.14159265 * (.35)^3
Volume = (4 / 3) * 3.14159265 * 0.042875
Volume = 0.17959438 cc
1 cc of steel = 7.8 g
Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc
1 kg = 128.205 cc
Number of ball bearings we can make = 128.205 / 0.17959438
Equals 713.86
Step-by-step explanation:
