Answer:
Step-by-step explanation:
Given that there are 3 sets such that there are 100 elements in A1, 1000 in A2, and 10,000 in A3
a) If A1 ⊆ A2 and A2 ⊆ A3
then union will contain the same number of elements as that of A3
i.e. 
b) If the sets are pairwise disjoint.
union will contain the sum of elements of each set
c) If there are two elements common to each pair of sets and one element in all three sets
We subtract common elements pairwise and add common element in 3
i.e. 
Answer:
Option D
Step-by-step explanation:
By the property of intersecting chords,
If two chords are intersecting at a point inside a circle, product of lengths of the line segments on each chord is equal.
DI × EI = HI × GI
12 × EI = 8 × 6
EI = 
EI = 4
Therefore, Option D is the correct option.
Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?
x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6
y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6
Rectangular coordinates of the point = (x,y) =(-6,6)
Answer: Option a. (-6,6) </span>
So whole numbers include the negative numbers, the zero and the positive numbers.
We will examine each category,
1- For the negative numbers:
multiplying a negative number by a positive value will result is a negative value (negative values are less than positive values of course). Therefore, multiplying any negative number by 400 will give a negative value which will make the desired statement false.
2- For the zero:
multiplying any number by a zero will give a result of zero which is again less than positive numbers. So, if we multiply 400 by a zero, the result will be zero which will again make the desired statement false.
3- For positive numbers:
multiplying two positive numbers will result in a positive value. Since 400 is already greater than 15, therefore, multiplying 400 by any positive value will keep the statement true. Since we are looking for the smallest whole number, therefore, we will choose that number to be 1 which will give 400 when multiplied by 400 (this is the smallest possible value).
The answer is 1.
What is the question can't help with ought it
