Answer:
2⋅(x 3 −5)
________
5
Step-by-step explanation: I hope this really help!
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x3" was replaced by "x^3".
STEP
1
:
x3
Simplify ——
5
Equation at the end of step
1
:
x3
(2 • ——) - 2
5
STEP
2
:
Rewriting the whole as an Equivalent Fraction
2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 5 as the denominator :
2 2 • 5
2 = — = —————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
2x3 - (2 • 5) 2x3 - 10
————————————— = ————————
5 5
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
2x3 - 10 = 2 • (x3 - 5)
Trying to factor as a Difference of Cubes:
3.2 Factoring: x3 - 5
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
a3+b3
Check : 5 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(x) = x3 - 5
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -5.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,5
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 -6.00
-5 1 -5.00 -130.00
1 1 1.00 -4.00
5 1 5.00 120.00
Polynomial Roots Calculator found no rational roots
Final result :
2 • (x3 - 5)
————————————
5
