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3 years ago

Someone help! I’m not good at these problems!

Mathematics

2 answers:

Evgen [1.6K]3 years ago

5 0

Answer:

I beliive it is 16, but haven't done this in a bit haha

Step-by-step explanation:

So bisect means to "split in half" aka segment BD is directly in the middle of triangle ABC. This means we can look at the half of the triangle we know (ABD). We see a 16, so therefore x should be 16.

(again, hopefully I am correct)

Black_prince [1.1K]3 years ago

5 0

I think the answer is 16 I believe.

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What is the area of the trapezoid?

Aloiza [94]

Answer:

Step-by-step explanation:

A = $\frac{a+b}{2\\}$ h

= $\frac{3+5}{2}$ · 3

= 12 ft

I hope this help

6 0

3 years ago

Seven hundred twelve thousandths in standard form and expanded form

pav-90 [236]

Answer:

Standard: 0.712

Expanded: 0.7 + 0.01 + 0.002

Step-by-step explanation:

Seven hundred twelve thousandths

.tenths,hundredths,thousandths

0.712

Every number in expanded fits in its place.

0.712

^ ^ ^

0.7 0.01 0.002

7 0

3 years ago

How did i work this out?

bogdanovich [222]

knowing the answer is between 3 & 4 plug those as x and see what you get for answers than adjust the number accordingly

3^3+2(3) = 33 so its higher than 3

4^3 + 2(4) = 72 so it is lower than 4

try the middle so try 3.5

3.5^3 + 2(3.5) = 49.875

question states use 1 decimal place so now try 3.6

3.6^3+2(3.6) = 53.856

3.5 is closest

6 0

3 years ago

the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room

Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

$C.S.A.=2h(l+b)$

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

$C.S.A.=\text{Perimeter of the base} \times h$

Putting the given values, we get

$C.S.A.=18\times 3$

$C.S.A.=54$

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0

3 years ago

M(-5,9) and N(-2,7)<br> P(-3,-7) and Q(3,-5

jek_recluse [69]

Answer:

M=(4,112)=(4,5.5) A

Step-by-step explanation:

The midpoint for two points P=(px,py) and Q=(qx,qy) is M=(px+qx2,py+qy2).

We have that px=3, py=2, qx=5, qy=9.

Thus, M=(3+52,2+92)=(4,112).

7 0

2 years ago