Hint: Try using the Pythagorean thereom to solve it.
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:

As h approaches 0 from the positive side, then:

Thus, f'(c) = 0
Answer:
three-forth minus one-fifth times four
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
-49-35x+x=-3x-18
-49-34x=-3x-18
-34x+3x=-18+49
-31x=31
-31x/-31=31/-31
ansx=-1
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