3 years ago

What's the answer to this problem idk how to do this

1 answer:

5 0

What you need to do is plot both lines. The point where they intersect is the solution.

Let me know if you're still having trouble then

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What is the correct factorization of x^6-y^6

Soloha48 [4]

(x^3 - y^3)(x^3 + y^3)

You can get this by factoring based on the a^2 - b^2 model

3 0

3 years ago

Make c the subject: x=-b+(b²-4ac) divided by 2a The brackets mean square root

kipiarov [429]

$x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\
2ax=-b+\sqrt{b^2-4ac}\\
\sqrt{b^2-4ac}=2ax+b\\
b^2-4ac=(2ax+b)^2\\
-4ac=4a^2x^2+4abx+b^2-b^2\\
-4ac=4a^2x^2+4abx\\
c=-ax^2-bx$

7 0

2 years ago

Y = 5x + 7 2x + y = -5 Are the equations parallel, perpendicular, or neither?

Nezavi [6.7K]

Lines are neither perpendicular nor parallel.

Step-by-step explanation:

Step 1:

In equation 1, Y = 5X + 7

In equation 2, Y = -2X -5

Step 2:

Slope Intercept form Y =mX +c

Where m = Slope

Slope of line 1 = 5

Slope of line 2 = -2

m1 is not equal to m2. Hence it is not parallel.

m1 × m2 is not equal to -1. Hence they are not perpendicular.

3 0

3 years ago

Look at picture .. pls !!

sveticcg [70]

Answer:

Step-by-step explanation:

5 0

1 year ago

PLS HELP ASAP

MrMuchimi

Answer 38.6

Step-by-step explanation:

21 x .84 = 17.64

17.64 + 21 = 38.64

6 0

2 years ago