All categories

4 years ago

QUESTION:

Mathematics

1 answer:

kobusy [5.1K]4 years ago

7 0

Answer:

ANSWER IS 7.96

APPROXIMATELY 8

Step-by-step explanation:

$in \: the \: given \: figure \: \\ let \: ab = 6cm \: and \: bc = p \: and \: angle \: c = 37degrees \\ \tan(37) = \frac{6}{p} \\ p = \frac{6}{ \tan(37) } \\ therefore \: p = 7.96 \\ p \: approximately \: equals \: 8$

FOR THE VALUE OF TAN37 DEGREES USE YOUR CALCULATOR. 

 HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

You might be interested in

Who to tell if the question is rational or irrational

Flauer [41]

An irrational number can be written as a decimal, but not as a fraction. An irrational number has endless non-repeating digits to the right of the decimal point. Any number that can be written as a fraction or a ratio is a rational number. The product of any two rational numbers is therefore a rational number, because it too may be expressed as a fraction.

8 0

3 years ago

The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1, 6) . What is the solution of the equation 2x+4=10−4x ? Enter you

Yuliya22 [10]

Answer:

$x=1$

Step-by-step explanation:

we have

$f(x)=2x+4$ -----> equation A

$g(x)=10-4x$ ----> equation B

we know that

The solution of the system of equations is the point $(1,6)$

The solution of the equation $2x+4=10-4x$ is equal to the x-coordinate of the solution of the system of equations

therefore

The solution is $x=1$

7 0

4 years ago

Use ΔABC to answer the question that follows:

ruslelena [56]

Let's try to render the first part of the proof a bit more legibly.

Point F is a midpoint of Line segment AB

Point E is a midpoint of Line segment AC

Draw Line segment BE

Draw Line segment FC by Construction

Point G is the point of intersection between Line segment BE and Line segment FC Intersecting Lines Postulate

Draw Line segment AG by Construction

Point D is the point of intersection between Line segment AG and Line segment BC Intersecting Lines Postulate

Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH by Construction

OK, now we continue. We need to prove some parallel lines; statement 4 lets us do so.

IV Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC -------- Midsegment Theorem

Now that we've shown some segments parallel we extend that to collinear segments.

III Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC -------- Substitution

We have enough parallel lines to prove a parallelogram

I BGCH is a parallelogram -------- Properties of a Parallelogram (opposite sides are parallel)

Now we draw conclusions from that.

II Line segment BD ≅ Line segment DC -------- Properties of a Parallelogram (diagonals bisect each other)

Answer: IV III I II, second choice

8 0

4 years ago

Pearson math r 11-5 how many rectangles in all are in the design

Oliga [24]

The number is 6 you subtract to get the answer

7 0

4 years ago

−9+1/4(8n+16)=1/4(20n+4) help pls

vfiekz [6]

Answer:

N= -2

Step-by-step explanation:

7 0

2 years ago