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3 years ago

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If 15bx-20>35 where b is a positive constant which of the following best describes all possible values of 4-3bx

2 answers:

Anuta_ua [19.1K]3 years ago

8 0

Quora Open This sounds like a multiple-choice test question from a standardized test. But let's take a look at it. If 15bx – 20 > 35 ,where b is a positive constant ... So you are given an equation here. Next you are given something to compare it to. 4 – 3bx. So we want to go from 15bx – 20 to 4 – 3bx. The point is for you to think about the relationship. What is the relationship of -20 to 4? How would you turn -20 into 4? By dividing by -5. Of course, division by a negative means you have to reverse the direction of the inequality. 15bx – 20 > 35 15bx – 20 35 -5 -5 4 – 3bx < -7. Note. You will be given an option with the incorrect inequality! After all, they want to see whether you remember every part of handling an inequality like this. Notice that we didn't have to solve for x. We didn't have to do a lot to the equation. We just had to do enough. That's why it is important to take your time to read the problem carefully and think about what it wants.

kotegsom [21]3 years ago

6 0

Answer: Any values greater than -7

Explanation: answered it

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The speed of a 2. 0-kg object changes from 30 m/s to 40 m/s during a 5. 0-s time interval. During this same time interval, the v

abruzzese [7]

The magnitude of the average total force acting on the object during this time interval is equal to 20 Newton.

<u>Given the following data:</u>

Mass = 2.0 kg

Initial velocity = 30 m/s

Final velocity = 40 m/s

Time = 5.0 seconds.

Angle = 90°

To calculate the magnitude of the average total force acting on the object during this time interval:

<h3>Newton's Second Law of Motion</h3>

In order to solve for the force acting on the dummy, we would apply Newton's Second Law of Motion.

<u>Note:</u> The acceleration of an object is equal to the rate of change in velocity with respect to time.

Mathematically, Newton's Second Law of Motion is given by this formula;

$F = \frac{M(v\;-\;u)}{t}$

Substituting the given parameters into the formula, we have;

$F_A = \frac{2(30\;-\;0)}{5}\\\\F_A = \frac{2\times 30}{5}\\\\F_A = \frac{60}{5}$

Force A = 12 Newton.

<u>For the second force:</u>

$F_B = \frac{2(40\;-\;0)}{5}\\\\F_B = \frac{2\times 40}{5}\\\\F_B = \frac{80}{5}$

Force B = 16 Newton.

Now, we can calculate the magnitude of the average total force acting on the object during this time interval:

$F = \sqrt{F_A^2 + F_B^2} \\\\F = \sqrt{12^2 + 16^2}\\\\F = \sqrt{144 + 256}\\\\F=\sqrt{400}$

Total force = 20 Newton.

Read more on force here: brainly.com/question/1121817

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