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Setler [38]
3 years ago
9

If 15bx-20>35 where b is a positive constant which of the following best describes all possible values of 4-3bx

SAT
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
Quora Open This sounds like a multiple-choice test question from a standardized test. But let's take a look at it. If 15bx – 20 > 35 ,where b is a positive constant ... So you are given an equation here. Next you are given something to compare it to. 4 – 3bx. So we want to go from 15bx – 20 to 4 – 3bx. The point is for you to think about the relationship. What is the relationship of -20 to 4? How would you turn -20 into 4? By dividing by -5. Of course, division by a negative means you have to reverse the direction of the inequality. 15bx – 20 > 35 15bx – 20 35 -5 -5 4 – 3bx < -7. Note. You will be given an option with the incorrect inequality! After all, they want to see whether you remember every part of handling an inequality like this. Notice that we didn't have to solve for x. We didn't have to do a lot to the equation. We just had to do enough. That's why it is important to take your time to read the problem carefully and think about what it wants.
kotegsom [21]3 years ago
6 0

Answer: Any values greater than -7

Explanation: answered it

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2 years ago
company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul
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Sampling distribution involves the proportions of a data element in a given sample.

  • <em>The proportion of Good TV set is 0.67</em>
  • <em>The number of ways of selecting 5 from 6 TV sets is 6</em>
  • <em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

n = 6

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

Good = 4

So, the proportion (p) that are good are:

p = \frac{Good}{n}

p = \frac{4}{6}

p = 0.67

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 5

So, we have:

^6C_5 = \frac{6!}{(6 - 5)!5!}

^6C_5 = \frac{6!}{1!5!}

^6C_5 = \frac{6 \times 5!}{1 \times 5!}

^6C_5 = \frac{6}{1}

^6C_5 = 6

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

^nC_r = \frac{n!}{(n - r)!r!}

Where

r = 4

So, we have:

^6C_4 = \frac{6!}{(6 - 4)!4!}

^6C_4 = \frac{6!}{2!4!}

^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}

^6C_4 = \frac{30}{2}

^6C_4 = 15

So, the table is as follows:

\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

p = \frac{Good}{n}

<u>(d) The sampling distribution</u>

In (a), we have:

p = 0.67 --- proportion of Good TV

The sampling error is calculated as follows:

SE_n = |p - p_n|

So, we have:

\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]

Read more about sampling distributions at:

brainly.com/question/10554762

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Answer:

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Explanation:

Education empowers a person by opening doors to the job market, combating inequality, fostering solidarity, and promoting environmental stewardship. Education empowers people with the knowledge, skills and values they need to thrive and build a better world.

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Answer:

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Explanation:

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It has uneven drum heads, with one side bigger than the other and both can be played simultaneously or at the same time.

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3 years ago
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Which group of college students is typically offered scholarship?
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D. First time freshmen, current students, and transfer students.

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