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3241004551 [841]
3 years ago
13

How long is the arc intersected by a central angle of pi/3 radians in a circle with a radius of 6 ft? Round your answer to the n

earest tenth. Use 3.14 for pi
1.0 ft
5.7 ft
6.3 ft
7.0 ft
Mathematics
2 answers:
oksian1 [2.3K]3 years ago
6 0

Answer:

c;6.3 just took the test on edge.

Step-by-step explanation:

Vinil7 [7]3 years ago
4 0

<u>Answer:</u>

6.3 ft

<u>Step-by-step explanation:</u>

We are given,

the central angle of the arc = \frac{\pi} {3} } radians; and

radius of the arc = 6ft

Therefore using these values, we can find the length of the long arc.

Length of the arc = 6 × \pi / 3

Lenth of the arc = 2\pi = 2 × 3.14 = 6.28

Therefore, the length of the arc, rounded to the nearest tenth is 6.3 ft.

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Answer:

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Step-by-step explanation:

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3 years ago
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Simplify. Answer in simplest radical form
notka56 [123]
That would be
12 \sqrt{ - 5 }
8 0
3 years ago
Help I will be marking brainliest!!!
expeople1 [14]

Answer:

A. 51°

Step-by-step explanation:

By the theorem of intersecting secants.

m\angle B=\frac{1}{2} (m\widehat{LW} - m\widehat{MU})

44.5\degree =\frac{1}{2} (140\degree - m\widehat{MU})

2\times 44.5\degree = 140\degree - m\widehat{MU}

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m\widehat{MU} = 140\degree -89\degree

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8 0
2 years ago
Evaluate the following expression will give branliest<br> 256 to the power of 5/8
Nana76 [90]

Answer:

32

Step-by-step explanation:

The formula needed to solve this question by hand is:

x^{\frac{m}{n}} =\sqrt[n]{x^{m}}

256^(5/8) = 8th root of 256^5

256^(5/8) = 8th root of 1280

<u>256^(5/8) = 32</u>

5 0
2 years ago
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PLEASE HELP!!!
DIA [1.3K]
You would need 27 more dollars because f(x)=7x+2 plug in the 5 in x’s spot and you get 37 and so subtract it from 10 to get 27
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3 years ago
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