Question

The electrical force on a 2-coulomb charge is 60 Newtons (N). What is the magnitude of the electric field at the place where the charge is located?

Answer 1

Explanation:

The given data is as follows.

            Charge (q) = 2 coulomb,        Force (F) = 60 N

Now, it is known that the relation between electric field, force and charge is as follows.

       Magnitude of electric field (E) = $\frac{Force}{charge}$

Hence, putting the given values into the above formula as follows.

              Electric field (E) = $\frac{Force}{charge}$

                                         = $\frac{60 N}{2 C}$

                                         = 30 N/C

Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.