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earnstyle [38]
3 years ago
13

A ball has m=10 kg and v=10 m/s. It has the same momentum as which of the following?

Physics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of 100\; \rm kg \cdot m \cdot s^{-1} each, same as that of the 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}. Assumption: all four balls are moving in the same direction.

Explanation:

The momentum p of an object is equal to the product of its mass m and its velocity v.

Momentum of a 10\; \rm kg ball moving at 10\; \rm m \cdot s^{-1}:

p = m \cdot v = 10\; \rm kg \times 10\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m \cdot s^{-1}.

Similarly:

  • Momentum of the ball in choice a: 100 \; \rm kg \times 1\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice b: 5 \; \rm kg \times 20\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.
  • Momentum of the ball in choice c: 2 \; \rm kg \times 50\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}.

Hence the conclusion that these balls have the same momentum.

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Maksim231197 [3]

Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

Given that

q₁ = 5 μ C

q₂ = - 4 μ C

The distance between charges = 50 cm

d= 50 cm

Lets take at distance x from the charge μ C ,the electrical field is zero.

That is why the distance from the charge - 4 μ C =  50 - x cm

We know that ,electric field is given as

E=K\dfrac{q}{r^2}

K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\

Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

3 0
3 years ago
During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintain
Cerrena [4.2K]

Answer:

Explanation:

Given that

Total race distance is 400m

Her initial velocity was 0m/s²

At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²

Using equation of motion

Let determine her constant acceleration

v²=u²+2as

12²=0²+2×a×100

144=0+200a

144=200a

a=144/200

a=0.72m/s²

Then we want to know her position after another 10second

So total time is 10+12=22seconds

Then, using equation of motion

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S=ut+½at²

S=0•t+½×0.72×22²

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7 0
4 years ago
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expeople1 [14]

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In a situation where a car is rolling back down the hill it is facing up, there could be one or more of several situations at hand.

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One other thing, is that clutches work both ways. Since only friction holds them together, the torque exerted by the wheels back through the drive-train to the clutch can cause the plates to slip when they are not completely engaged. This results in the wheels moving independently of the running engine, as the clutch is separating the forces they would exert on each other.

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If it's not the engine or the clutch which are both behaving as normal, and we're still assuming it's an auto, there could be a problem with the car's computer system, transmission, clutch or gearbox that is causing the slippage. I would assume this is less likely, but it might be worth checking if it happens to your car. your frickin' welcome

6 0
3 years ago
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What is the momentum of an object that has a mass of 0.03 grams and a velocity of 1200 m/s2
ruslelena [56]

answer is 36

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3 years ago
What are the characteristics of S waves?
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I think the answer is D
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