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3 years ago

Which type of energy moves from one object to another by touching?

Physics

2 answers:

leonid [27]3 years ago

6 0

Answer:

Conduction mode

Explanation:

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irinina [24]3 years ago

3 0

Radiation type of energy moves

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An object with a mass of 1.5 kg changes its velocity +15 m/s during a time interval of 3.5 seconds what impulse was delivered to

Arada [10]

The answer is 10.5 kg m/s

Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt

Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a

Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt

So:
a = Δv/Δt ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)

It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s

I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.

7 0

4 years ago

2. Two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one o

rusak2 [61]

The rod is stretched due to the force of gravitational attraction.

The magnitude of the deformation force on the rod is -GMm×((1/r² + 1/(L+r)²)

<h3>What is gravity?</h3>

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given are two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one of the objects is located at a distance of r away from the center of a uniform spherical planet with mass M. Assume that m is very small so that you can ignore the gravitational force between the two small (green) objects.

Let the mass closer to the planet is A and the other is B

FA = Force on planet A = -GMm/r²

FB = Force on planet B = -GMm/(L+r)²

Net Force on the rod is given by the addition of the individual forces.

Fnet= FA + FB = -GMm/r² -GMm/(L+r)²

Fnet = -GMm×((1/r² + 1/(L+r)²)

Thus, the magnitude of the deformation force on the rod is derived above.

A experience more force than B, so A will stretch out from B. Hence the force is stretching the rod.

Learn more about gravity.

brainly.com/question/4014727

#SPJ1

8 0

2 years ago

A 2.0 kg block on a horizontal frictionless surface is attached to a spring whose force constant is 590 N/m. The block is pulled

SVETLANKA909090 [29]

Answer:

The value is $v = -0.04 \ m/s$

Explanation:

From the question we are told that

The mass of the block is $m = 2.0 \ kg$

The force constant of the spring is $k = 590 \ N/m$

The amplitude is $A = + 0.080$

The time consider is $t = 0.10 \ s$

Generally the angular velocity of this block is mathematically represented as

$w = \sqrt{\frac{k}{m} }$

=> $w = \sqrt{\frac{590}{2} }$

=> $w = 17.18 \ rad/s$

Given that the block undergoes simple harmonic motion the velocity is mathematically represented as

$v = -A w sin (w* t )$

=> $v = -0.080 * 17.18 sin (17.18* 0.10 )$

=> $v = -0.04 \ m/s$

7 0

4 years ago

A spherical conducting shell has charge Q. A point charge q is placed at the center of the cavity. The charge on the inner surfa

FinnZ [79.3K]

Answer:d

Explanation:

From Gauss law Electric field inside a surface is directly proportional to the charge enclosed in it.

Electric field inside a spherical shell is zero and hence there is no charge inside the spherical shell because q charge induces a -q charge on inside surface of spherical shell.

and to counter it there is q charge on the surface. So total charge outside the surface is Q+q

7 0

3 years ago

A pressure of 400 Pa is applied to an area of 2.5 m2.What force applies this pressure?

Irina-Kira [14]

F = 400 Pa x 2.5 m2
F = 1 kN

4 0

3 years ago