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ch4aika [34]
3 years ago
7

Write the slope intercept form of the equation of the line through the given points.

Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

You use the formula (y to the second power minus y to the first power minus the same formula with the two different points

Step-by-step explanation:

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I am thinking of six different odd numbers, the mean of the numbers is 16, the median is 15, the range is 26, the greatest numbe
Sedaia [141]

Answer:

Step-by-step explanation:

information from the range

If the range is 26 and the largest number is 31 then the smallest number is 31 - 26  = 5

Information from the median

The median must consist of 2 numbers because we have 6 integers for the data and median must consist of the middle 2. Since we are told that the median is 15 and we need 2 integers the other integer must  be 15 as well..

So what do we know so far.

5      15 15         31

Information from the mean

There are six integers making up the series of numbers. The mean is 16. Therefore all 6 integers added together must be 6 * 16 = 96

What do we have so for?

5 + 15 + 15 + 31 = 66

What do the other two numbers sum to?

96 -66 = 30

Getting the answer.

The first number to try must be 13. It has to be below 15 (the median and odd. That's 13).

So now we have

5 13 15 15 ___ 31

But from the mean we need 30

30 - 13 = 17

And we have a winner because 17 is above 15.

Answer

5 13 15 15 17 31

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=4%20%5Cfrac%7B2%7D%7B3%7D%20%20%20%2B%205x%20%3D%207%20%20-%202x" id="TexFormula1" title="4 \f
Delicious77 [7]

4 2/3+5x=7-2x

Add 2x to both sides.

4 2/3+7x=7

Subtract 4 2/3 on both sides.

7x=2 1/3

7x=7/3

Divide by 7 on both sides.

x=1/3

answer: x=1/3

5 0
3 years ago
Read 2 more answers
When I have more than two samples of proportions, I can use ANOVA to test for significant differences. a. True b. False
Cerrena [4.2K]
False I took the quiz and it was right
5 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
A large oak tree has 2 x 10⁵ leaves during
Rom4ik [11]
I’m pretty sure it’s this 200,000
4 0
3 years ago
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