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3 years ago

Simplify 18 - 2[x + (x - 5)]. please i keep getting it wrong

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

8 0

18-2[x+(x-5)]
18-2[2x-5]
18-4x+10
28-4x
-7+x or x-7 <-- Simplified version.
x=7 <-- What x equals.

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3 years ago

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3 years ago

Can someone PLEASE solve this quadratic equation by factoring with the steps? :(

salantis [7]

Answer:

There are no simple factors to this expression. You can however solve for x, giving you:

x = -1 ± √(y + 3)

Step-by-step explanation:

There is no simple pair of factors to this equation, so we'll have to go through the full process. You can see that by observing that there is no pair of rational numbers that add to make 2 and multiply to make -2. We can however solve for x:

$y = x^2 + 2x - 2\\y + 2 = x^2 + 2x\\y + 3 = x^2 + 2x + 1\\y + 3 = (x + 1)^2\\(x + 1)^2 = y + 3\\x + 1 = \pm \sqrt{y + 3}\\x = -1 \pm \sqrt{y + 3}$

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3 years ago

Just need the answer please

Kisachek [45]

Answer:

19.34cm

Step-by-step explanation:

Rigth Angled triangle

use SOHCAHTOA

Cos°=adj/hyp

Cos 71=6.3/BC

BC=6.3/COS 71

COS 71°= 0.3256

BC=6.3/0.3256

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3 years ago

What is the value of the x variable in the solution to the following system of equations? 4x − 3y = 3 5x − 4y = 3

andrew-mc [135]

Solve 4x − 3y = 3 and 5x − 4y = 3

Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
 $\frac{4x}{4} = \frac{3x+3}{4}$ [Divide both sides by 4]
x= $\frac{3}{4}y+ \frac{3}{4}$

Step 2: Substitute $\frac{3}{4}y+ \frac{3}{4}$ for x in 5x-4y=3
5x-4y=3
5( $\frac{3}{4}y+ \frac{3}{4}$ )-4y=3
 $\frac{-1}{4}y+ \frac{15}{4} =3$
$\frac{-1}{4}y+ \frac{15}{4} - \frac{15}{4} =3- \frac{15}{4}$ [Subtract $\frac{15}{4}$ to both sides]
$\frac{-1}{4}y= \frac{-3}{4}$
$\frac{ \frac{-1}{4}y}{ \frac{-1}{4} }= \frac{\frac{-3}{4} }{ \frac{-1}{4}}$ [Divide both sides by $\frac{-1}{4}$ ]
y = 3

Step 3: Substitute 3 for y in x = $\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}(3)+ \frac{3}{4}$
x = 3

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3 years ago