All categories

3 years ago

Scale factor: 1:4

Mathematics

1 answer:

mojhsa [17]3 years ago

5 0

Answer:

The area of the real object is 480 square cm

Step-by-step explanation:

Scaling

Objects can be represented in a reduced or augmented size by using scaling which is basically multiplying or dividing by a constant factor.

The scale factor (f) converts a real dimension (x) into a scaled dimension (y) and vice-versa and is computed as:

$\displaystyle f=\frac{x}{y}$

If the magnitudes are areas, the scaling factor is squared:

$\displaystyle f^2=\left(\frac{x}{y}\right)^2$

And for volumes:

$\displaystyle f^3=\left(\frac{x}{y}\right)^3$

If the scale factor is 4, the area of a 30 square cm object is scaled to:

30 * 4^2 = 480

The area of the real object is 480 square cm

You might be interested in

Which option for college funding can parents start when children are still very young? College savings account scholarship work-

kap26 [50]

Answer:

Your answer would be A: "college savings account."

Step-by-step explanation:

Got it right on edge.

6 0

3 years ago

Read 2 more answers

If A = {1, 2, 3} and B = {1, 2, 2, 3}, is B ⊆ A? If so, is A = B?

Serjik [45]

Answer:

yes, yes

Step-by-step explanation:

B={1,2,3} it doesn't matter if it has ten 2's or one!

so A=B and A⊆B

4 0

3 years ago

Which point on the number line represents the number that can be added to-3

vova2212 [387]

Answer: 3

Step-by-step explanation: This is because the 2 numbers are opposites, which cancel each other out, going back to zero.

8 0

3 years ago

Read 2 more answers

CAN ANYONE PLEASE EXPLAIN TO ME WHAT ON EARTH THIS MEANS

Shtirlitz [24]

the work that you're required to do has to contain all three requirements in order to earn the maximum number of points, and it also has to be creative (meaning no copying other people's work)

6 0

3 years ago

(Y+3)(y^2-3y+9) A. Y^3+27 B. Y^3-27 C. Y^3-6y^2+27 D. Y^3+6y^2+27

KonstantinChe [14]

Answer:

A) y^3+27

Step-by-step explanation:

There are two ways of solving this problem:

1. Recognizing this as the factored form of the sum of perfect cubes

2. Distribute and add the like terms.

1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:

$(y+3)(y^2-3y+9)=y(y^2-3y+9)+3(y^2-3y+9)$

$y(y^2-3y+9)+3(y^2-3y+9)=y^3-3y^2+9y+3y^2-9y+27$

After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:

$y^3-3y^2+9y+3y^2-9y+27=y^3+27$

2. You know how you can factor the difference of perfect squares?

As an example:

$a^2-b^2=(a+b)(a-b)$

Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

$a^3-b^3=(a-b)(a^2+ab+b^2)$

Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27

6 0

3 years ago