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Bas_tet [7]
3 years ago
13

I need help as soon as posible

Chemistry
1 answer:
In-s [12.5K]3 years ago
3 0
2. CO
3.O2
4.NH3
5.NO
6.NO2
7.CO2
8.H2
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The km of an enzyme is 5. 0 mm. Calculate the substrate concentration when this enzyme operates at one‑quarter of its maximum ra
Makovka662 [10]

The substrate concentration of the enzyme operating at one‑quarter of its maximum rate is = 0.333.

Relationship between Km and substrate concentration is -

Km is the concentration of substrate.It allows the enzyme to achieve half Vmax. High Km enzyme requires a higher concentration of substrate to get Vmax. Since, Km is a constant. If the substrate concentration is increased, it has no effect on it.

An enzyme with a high Km has a low affinity for its substrate. The substrate concentration Km corresponds to the substrate concentration.

The substrate concentration at which the reaction rate of the enzyme-catalyzed reaction is half of the maximum reaction rate Vmax.

The equation is:

                <em>V₀ = </em><u><em>Vmax [S] </em></u>

<em>                          [S] + Km</em>

Here,

V₀ is initial rate,

Km is the dissociation constant between the substrate and the enzyme,

Vmax is the maximum rate, and

S is the concentration of substrate.

taking fraction of V₀ and Vmax :

<u><em>    V₀    </em></u><em> = </em><u><em>     [S</em></u><em>]</em><u><em>     </em></u><em>  </em>

<em>Vmax      [S] + Km</em>

<u><em>   </em></u><u>V₀   </u> =   <u>   0.5Km   </u>  = 0.333

Vmax       1.50 + Km

Therefore, the substrate concentration of this enzyme operating at one‑quarter of its maximum rate is = 0.333.

To learn more about substrate concentration,

brainly.com/question/18237939

#SPJ4

3 0
10 months ago
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid at 0°C?
Marrrta [24]
Energy released from changing the phase of a substance from the liquid phase to solid phase can be calculated by using the specific latent heat of fusion. The heat of fusion of water at 0 degrees Celsius is 334 J/g. Calculation are as follows:
<span>
Energy = 5 grams x 334 J/g
</span><span>Energy = 1670 J</span>
4 0
2 years ago
Please help!!!!!! Name 3 differences between vascular and non vascular plants
Arlecino [84]
Am letting the picture doing the talk.

8 0
3 years ago
First, get about 20 mL of the quinine stock solution in a clean beaker to prepare 250 mL of about 2 ppm quinine in 0.05 M H2SO4.
iris [78.8K]

Answer:

Volume of acid, Va=250mL; Volume of quinine,Vb=20mL; Molarity of acid, Ma=0.05M.

Molar mass of acid= H2+S+O4= 2+32+(16X4)= 2+32+64=98g

Concentration of acid, Ca= Molar mass of acid/ Ma =98/0.05=1960g/mol

Explanation: To calculate concentration of quinine, Cb is as follow

Va*Ca=Vb*Cb

∴ Cb=Va*Ca/Vb =250*1960/20 =24500g/mol

5 0
3 years ago
The proximate reason for the uptake by plants of nutrients like ammonium nitrate is?
Blizzard [7]

The proximate reason for the uptake by plants of nutrients like ammonium nitrate is homeostatis

<h3>What is homeostasis?</h3>

Homeostasis refers to an organism's ability to regulate various physiological processes to keep internal states steady and balanced.

<h3>How does plant perform homeostatis?</h3>

As water leaves the plant tissues into the atmosphere, it takes energy with it in the form of heat.

Much like when we sweat, this allows the plant to cool and maintain homeostasis.

Similarly, the same process allows plants to  absorb nutrient like ammonium nitrate.

Thus, the proximate reason for the uptake by plants of nutrients like ammonium nitrate is homeostatis.

Learn more about homeostatis here: brainly.com/question/1046675

#SPJ1

8 0
1 year ago
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