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erma4kov [3.2K]
3 years ago
14

How many moles of N are in 0.203 g of N2O?

Chemistry
2 answers:
kondor19780726 [428]3 years ago
7 0
Molar mass N₂O = 14 x 2 + 16 => 44.0 g/mol

1 mole ---------- 44.0 g
moles ------------ 0.203 g

 0.203 / 44 => 0.004613 moles

1 mol N2O <span>contains 2 atoms N , therefore:

0.004613 x 2 => 0.009226 moles of N

hope this helps!</span>
Mandarinka [93]3 years ago
6 0
To calculate the number of moles of an element in the given mass of a compound, we need to convert mass into moles by using its molecular eight then relate the ratio of the elements.

0.203 g N2O (1 mol / 44.01 g N2O) ( 2 mol N / 1 mol N2O) = 9.23 x 10^-3 mol N
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Iron oxide and hydrogen react to form iron and water in the following chemical equation:
just olya [345]

Answer:

The answer to your question is 245.9 g of Fe₂O₃

Explanation:

Data

grams of Fe₂O₃ = ?

grams of Fe = 172 g

Balanced chemical reaction

                Fe₂O₃  +  3H₂   ⇒   2Fe  +  3H₂O

Process

1.- Calculate the molar mass of of Iron Oxide and Iron

Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g

2Fe = 2 x 56 = 112 g

2.- Use proportions and cross multiplication to solve this problem

                  160 g of Fe₂O₃ --------------- 112 g of Fe

                      x                   ---------------- 172 g of Fe

                      x = (172 x 160)/112

                      x = 27520/112

                     x = 245.9 g of Fe₂O₃

7 0
3 years ago
In a fizzy drink container how is steel separated from aluminium
barxatty [35]

Answer:

By filtration

Explanation:

In the container, pour water and shake the mixture very well.

Pour the mixture in a clean container thro<u>ugh</u> a <em><u>filt</u></em><em><u>er</u></em><em><u> </u></em><em><u>tunnel</u></em> and steel with be the residue and aluminium will be in water.

Add dilute Ammonia solution to the filtrate to precipitate it and burn until aluminium solid is obtained.

5 0
3 years ago
What is the difference between the Lewis model and the valence-shell electron pair repulsion (VSEPR) model?
grandymaker [24]

Answer: only the VSEPR mode shows the geometric shape of a formula.

8 0
3 years ago
A flask is filled with 50.0 ml of 0.15 M HCl acid. Exactly 0.054 grams of CaCo3 are placed in the acid,
ira [324]

Answer:

See explanation

Explanation:

2HCl(aq) + CaCO3(aq) ------->CaCl2(aq) + CO2(g) + H2O(l)

Number of moles of acid present = 50/1000 * 0.15 = 0.0075 moles

Number of moles of calcium carbonate = 0.054g/100 g/mol = 0.00054 moles

2 moles of HCl reacts with 1 mole of calcium carbonate

x moles of HCl reacts with 0.00054 moles of calcium carbonate

x = 2 *  0.00054/1

x = 0.00108 moles of HCl

Amount of acid left = 0.0075 moles - 0.0075 moles = 0.00642 moles

Reaction of HCl and NaOH

HCl(aq) + NaOH(aq) ------> NaCl(aq) + H2O(l)

Since the reaction is in the mole ratio of 1:1

0.00642 moles of HCl is neutralized by 0.00642 moles of NaOH

8 0
3 years ago
A compound is 40% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula?
Ahat [919]

Answer:

                           O        H        C

Moles in 100g  3.33   6.65    3.33

Ratio                  1.00   2.00    1.00

Possible empirical formula = OH_{2}C

6 0
3 years ago
Read 2 more answers
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