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erma4kov [3.2K]
3 years ago
14

How many moles of N are in 0.203 g of N2O?

Chemistry
2 answers:
kondor19780726 [428]3 years ago
7 0
Molar mass N₂O = 14 x 2 + 16 => 44.0 g/mol

1 mole ---------- 44.0 g
moles ------------ 0.203 g

 0.203 / 44 => 0.004613 moles

1 mol N2O <span>contains 2 atoms N , therefore:

0.004613 x 2 => 0.009226 moles of N

hope this helps!</span>
Mandarinka [93]3 years ago
6 0
To calculate the number of moles of an element in the given mass of a compound, we need to convert mass into moles by using its molecular eight then relate the ratio of the elements.

0.203 g N2O (1 mol / 44.01 g N2O) ( 2 mol N / 1 mol N2O) = 9.23 x 10^-3 mol N
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Answer:

0.500 mol/dm³

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (mol/dm³)

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Va = volume of acid (cm³)

Vb = volume of base (cm³)

In accordance to the information provided in this question is;

Va = 5cm³

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12 × 5 = Cb × 250

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Cb = 0.500 mol/dm³

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3 years ago
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Answer:

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3 years ago
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lapo4ka [179]
Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

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=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

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