Answer:
The answer to your question is 245.9 g of Fe₂O₃
Explanation:
Data
grams of Fe₂O₃ = ?
grams of Fe = 172 g
Balanced chemical reaction
Fe₂O₃ + 3H₂ ⇒ 2Fe + 3H₂O
Process
1.- Calculate the molar mass of of Iron Oxide and Iron
Fe₂O₃ = (2 x 56) + (3 x 16) = 112 + 48 = 160 g
2Fe = 2 x 56 = 112 g
2.- Use proportions and cross multiplication to solve this problem
160 g of Fe₂O₃ --------------- 112 g of Fe
x ---------------- 172 g of Fe
x = (172 x 160)/112
x = 27520/112
x = 245.9 g of Fe₂O₃
Answer:
By filtration
Explanation:
In the container, pour water and shake the mixture very well.
Pour the mixture in a clean container thro<u>ugh</u> a <em><u>filt</u></em><em><u>er</u></em><em><u> </u></em><em><u>tunnel</u></em> and steel with be the residue and aluminium will be in water.
Add dilute Ammonia solution to the filtrate to precipitate it and burn until aluminium solid is obtained.
Answer: only the VSEPR mode shows the geometric shape of a formula.
Answer:
See explanation
Explanation:
2HCl(aq) + CaCO3(aq) ------->CaCl2(aq) + CO2(g) + H2O(l)
Number of moles of acid present = 50/1000 * 0.15 = 0.0075 moles
Number of moles of calcium carbonate = 0.054g/100 g/mol = 0.00054 moles
2 moles of HCl reacts with 1 mole of calcium carbonate
x moles of HCl reacts with 0.00054 moles of calcium carbonate
x = 2 * 0.00054/1
x = 0.00108 moles of HCl
Amount of acid left = 0.0075 moles - 0.0075 moles = 0.00642 moles
Reaction of HCl and NaOH
HCl(aq) + NaOH(aq) ------> NaCl(aq) + H2O(l)
Since the reaction is in the mole ratio of 1:1
0.00642 moles of HCl is neutralized by 0.00642 moles of NaOH
Answer:
O H C
Moles in 100g 3.33 6.65 3.33
Ratio 1.00 2.00 1.00
Possible empirical formula = 