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arlik [135]
3 years ago
7

How many moles of H2O moles of H2O are needed to produce 55.7 moles of H2?

Chemistry
1 answer:
Fofino [41]3 years ago
6 0

<u>Answer:</u> 55.7 moles of H_2O are needed to produce the given amount of H_2

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given values:

Moles of H_2 = 55.7 moles

The chemical equation for the decomposition of water follows:

2H_2O\rightarrow 2H_2+O_2

By the stoichiometry of the reaction:

If 2 moles of hydrogen gas is produced from 2 moles of water

So, 55.7 moles of hydrogen gas will be produced by = \frac{2}{2}\times 55.7=55.7mol of water

Hence, 55.7 moles of H_2O are needed to produce the given amount of H_2

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A chemical reaction involves reactant species A, B, and C. Leaving all other factors identical, doubling the concentration of sp
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Answer:

Rate = k . [B]² . [C]

Explanation:

The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.

Rate=k.[A]^{x} .[B]^{y} .[C]^{z}

where,

k is the rate constant

x, y, z are the reaction orders.

  • <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
  • <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
  • The rate of the reaction is linearly dependent on the concentration of C. This means that the reaction order for C is z = 1, that is, a linear dependence.

All in all, the rate equation is:

Rate = k . [B]² . [C]

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Which of the following best describes weight? The amount of space an object takes up The amount of matter in an object The force
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A buffer is prepared by adding 139 mL of 0.39 M NH3 to 169 mL of 0.19 M NH4NO3. What is the pH of the final solution? (Assume th
Paha777 [63]

Answer:

pH = 9.48

Explanation:

We have first to realize that NH₃ is a weak base:

NH₃ + H₂O ⇔ NH₄⁺ + OH⁻     Kb = 1.8 x 10⁻⁵

and we are adding this weak base to a solution of NH₄NO₃ which being a salt dissociates 100 % in water.

Effectively what we have here is a buffer of a weak base and its conjugate acid. Therefore, we need the Henderson-Hasselbach formula for weak bases given by:

pOH = pKb + log ( [ conjugate acid ] / [  weak base ]

mol NH₃ = 0.139 L x 0.39 M = 0.054 mol

mol NH₄⁺ = 0.169 L x 0.19 M = 0.032 mol

Now we have all the information required to calculate the pOH ( Note that we dont have to calculate the concentrations since in the formula they are a ratio and the volume will cancel out)

pOH = -log(1.8 x 10⁻⁵) + log ( 0.032/0.054) = 4.52

pOH + pH = 14 ⇒ pH = 14 - 4.52 = 9.48

The solution is basic which agrees  with NH₃ being  a weak base.

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