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3 years ago

Could the other molecules in this simulation (argon, oxygen, and water) be considered pure substances? Explain your thinking.

Chemistry

1 answer:

Komok [63]3 years ago

5 0

Answer:

A water molecule consists of three atoms; an oxygen atom and two hydrogen atoms, which are bond together like little magnets. The atoms consist of matter that has a nucleus in the centre. The difference between atoms is expressed by atomic numbers. ... There are also uncharged particles in the nucleus, called neutrons.

Explanation:

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Please answer quickly

Stolb23 [73]

Inherited it from his grandfather

8 0

3 years ago

a baseball player hits a baseball with a bat.The mass of the ball is 0.25kg.The ball accelerates at 200m/s2

34kurt

Answer:

50N

Explanation:

Force (N) = mass (kg) × acceleration (m/s²)

0.25kg times 200m/s² = 50N

5 0

3 years ago

How many moles of atoms are there in 8.0 g of Mg?

JulsSmile [24]

Answer:

0.33

Explanation:

1mol=24

x=8

=0.33

5 0

4 years ago

Read 2 more answers

How many oxygen (O) atoms are involved in this chemical reaction? 2Fe(OH)3 — Fe2O3 + 3H20

kenny6666 [7]

Answer:

6 oxygen atoms

Explanation:

From the equation,

2Fe(OH)₃ → Fe₂O₃ + 3H₂O

From the reactant (left hand side) we have 2 moles of Fe(OH)₃ having (2 * 3 = 6) atoms of oxygen and decomposed to give Fe₂O₃ which contains 3 atoms of oxygen and 3 moles of water that also contains 3 atoms of oxygen.

Since the number of oxygen participating in the reaction is independent on the product (not a reversible reaction) then the total number of oxygen atoms participating in the reaction is 6

7 0

4 years ago

The arsenic in a 1.223 g sample of a pesticide was converted to H3AsO4 by suitable treatment. The acid was then neutralized, and

Vladimir79 [104]

Answer:

5.471% As₂O₃ in the sample.

Explanation:

...the reaction is: Ag+ + SCN- => AgSCN(s) Calculate the percent As2O3 in the sample. (F.W. As2O3 = 197.84 g/mol).

First, with the amount of KSCN we can find the moles of Ag in the filtrates. As we know the amount of Ag added we can know the precipitate of Ag and the moles of AsO₄ = 1/2 moles of As₂O₃ in the sample:

Moles KSCN = Moles Ag⁺ in the filtrate:

0.01127L * (0.100mol / L)= 0.001127moles Ag⁺

Total moles Ag⁺:

0.0400L * (0.0781mol/L) = 0.0031564 moles Ag⁺

Moles of Ag⁺ in the precipitate:

0.0031564 - 0.001127 = 0.0020294 moles Ag⁺

Moles AsO₄ = Moles As:

0.0020294 moles Ag⁺ * (1mol As / 3 moles Ag⁺) = 6.765x10⁻⁴ moles AsO₄

Moles As₂O₃:

6.765x10⁻⁴ moles AsO₄ * (1 mol As₂O₃ / 2 mol AsO₄) =

3.382x10⁻⁴ moles As₂O₃

Mass As₂O₃:

3.382x10⁻⁴ moles As₂O₃ * (197.84g/mol) = 0.0669g As₂O₃

Percent is:

0.0669g As₂O₃ / 1.223g sample * 100 =

<h3>5.471% As₂O₃ in the sample</h3>

7 0

3 years ago