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Ulleksa [173]
3 years ago
6

Calculate the percentage of copper in copper oxide

Chemistry
1 answer:
WITCHER [35]3 years ago
5 0

Well, look up the atomic weights of copper and oxygen; add them appropriately; divide the total for the copper by the total for the molecule; then multiply by 100 to get it as a percentage.

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I pls help me this is the question:<br><br>define the following terms below​
Travka [436]

Answer:

natural resources: materials or substances such as minerals, forests, water, and fertile land that occur in nature and can be used for economic gain.

renewable resources:  a natural resource that is unlimited or that is naturally replenished rather quickly, such as sunlight or water

non renewable resources: (also called a finite resource) is a natural resource that cannot be readily replaced by natural means at a pace quick enough to keep up with consumption.

8 0
3 years ago
I need help please and thank you
Alenkasestr [34]

Answer:

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Explanation:

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4 0
3 years ago
A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?
neonofarm [45]

Answer:

\boxed {\boxed {\sf 40.4299 \ Joules}}

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

PE= m \times g \times h

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

  • m= 1.85 kg
  • g= 9.8 m/s²
  • h= 2.23 m

Substitute the values into the formula.

PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m

Multiply the first 2 numbers together.

PE=18.13 \ kg*m/s^2 *2.23 \ m

Multiply again.

PE= 40.4299 \ kg*m^2/s^2

  • 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
  • Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

PE= 40.4299 \ J

The textbook has <u>40.4299 Joules of potential energy.</u>

7 0
3 years ago
It is the one in the middle i listened to the first person and i got it wrong by the way this is the answer for edge2020 sience
Anna11 [10]

Answer:

for what school? It's different for all sadly :(

Explanation:

6 0
3 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula
ki77a [65]
The standard atomic weight of a C is 12, and the standard atomic weight of a H is 1.  So to find molar ratio of C and H in the compound: 60.0/12=5, 5.05/1=5. This means the molar ratio of C and H is 5:5, thus 1:1.  Assuming the molecular formula is CnHn, to find molar mass: 12n + 1n = 78.12.  n=78.12/(12+1) = 6.  So the compound's molecular formula is C6H6, benzene.
4 0
3 years ago
Read 2 more answers
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