Well, look up the atomic weights of copper and oxygen; add them appropriately; divide the total for the copper by the total for the molecule; then multiply by 100 to get it as a percentage.
<span>Divide each % value by respective atomic mass Mn = 63.0/54.94 = 1.1467 O = 37/16 =2.3125 Divide by smaller value Mn = 1 O = 2.3125/1.1467 = 2 Empirical formula = MnO2</span>
