It is called an indirect instance of watching, noticing, or making a statement. you might also be thinking of quiet and sneaky instance of watching, noticing, or making a statement but that is when you sense something that is below the point where something begins or changes of the senses.
The answer is: all true
<span>A. As the pressure of the gas increased, the volume of the gas decreased.
It is clear that if you compare the data on the left side. When the pressure increased the volume is decreased.
B. For all pairs of data of pressure and volume, P • V was appoximately the same.
The pressure is inversely related to the volume. You can take two data to prove it. Let use the first and second data
V * P= 1.03 * 50= 51.5
</span>V * P= <span>1.08 * 47.5= 51.3
C. For all pairs of data of pressure and volume, P • V mr001-1.jpg k for the same value k.
D. The regression equation was of the form V = kP–1 (which is the same as V = k/P).
The value of k can be expressed as k= P*V. If the equation is turned around, it could be expressed as V= k/P
The value of k is constant on different data, proved by the calculation on the second statement above. The value of k should be around 51.5
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The specific heat in, J /g °C of copper is 0.386J/g°C
HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:
- The specific capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
∆T = change in temperature (°C)
c = specific heat capacity (J/g°C)
For a colorimeter, the following equation applies:
m.c.∆T (water) = - m.c.∆T (metal)
m = 50g
c = 4.184 J/g°C
∆T = 29.2 - 26°C = 3.2°C
m = 70g
c = ?
∆T = 29.2 - 54°C = -24.8°C
m.c.∆T (water) = - m.c.∆T (metal)
50 × 4.184 × 3.2 = -(70 × c × -24.8)
669.44 = 1736c
c = 669.44 ÷ 1736
c = 0.386J/g°C
Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C
Learn more at: brainly.com/question/16787162?referrer=searchResults
Controlled because there is always going to be a control group and an experimental group so that you could see the difference in the results
