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DaniilM [7]
3 years ago
8

A student pipets 5.00 mL of a 5.103 M aqueous NaOH solution into a 250.00 mL volumetric flask and dilutes up to the mark with di

stilled water. What is the final molarity of the dilute solution?
Chemistry
1 answer:
Zina [86]3 years ago
6 0

Answer:

0.102 M.

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5 mL

Molarity of stock solution (M1) = 5.103 M

Volume of diluted solution (V2) = 250 mL

Molarity of diluted solution (V2) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M1V1 = M2V2

5.103 × 5 = M2 × 250

25.515 = M2 × 250

Divide both side by 250

M2 = 25.515 / 250

M2 = 0.102 M

Thus, the molarity of the diluted solution is 0.102 M.

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Cyclopropane is converted to propene in a first–order process with a rate constant of 5.4 × 10–2 hour–1 . The initial concentrat
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Answer:

The concentration of cyclopropane after 22.0 hour is 0.0457 M.

Explanation:

Conversion of cyclopropane into propene follows first order kinetics.

The integrated rate of first order kinetic is given by :

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The concentration of cyclopropane after 22.0 hour is 0.0457 M.

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