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Llana [10]
4 years ago
10

If your volume measurement is only good to two significant figures, will your results be more precise if you use mass measuremen

ts that have six significant figures. Is it true?
Physics
1 answer:
Rina8888 [55]4 years ago
4 0

Answer:

Measurement with six significant figure has a possibility of much greater accuracy than the measurement of only two significant figure.

Explanation:

  • When we measure an object in only two significant figures then we eliminate the possibility of getting close to higher accuracy as when the measurement is taken into six significant figures.
  • When we measure in six significant figures then we take the measurement into more finer fragments, we are able to measure very smaller variation as well. In other words we are taking the least count of the measurement to a more finer level than when measuring upto two significant figures.

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A particle with charge -5.60 nC is moving in a uniform magnetic field →B=−(1.25T) k The magnetic force on the particle is measur
chubhunter [2.5K]

Answer:

Explanation:

Force = q ( v x B)

- 5.6 x 10⁻⁹ (v x - 1.25 k )

- 3.4x 10⁻⁷i + 7.4 x 10⁻⁷j

Let v = ai+bj +ck

Force = - 5.6 x 10⁻⁹ [(ai+bj +ck) x - 1.25 k )]

= - 5.6 x 10⁻⁹ ( 1.25aj - 1.25bi )

= - 7 a j + 7 b i

( 7bi - 7aj ) x 10⁻⁹

Comparing with given force

7b x 10⁻⁹ b = - 3.4 x 10⁻⁷

b = - 48.57

- 7 a x 10⁻⁹ = 7.4 x 10⁻⁷

a = - 105.7

velocity

= -105.7 i - 48.57 j + ck

b ) Component along k can not be obtained .

c ) v . F = ( -105.7 i - 48.57 j + ck ) . −(3.40×10−7N) ˆı +(7.40×10−7N) ˆȷ

= 105.7 x 3.4 x 10⁻⁷ - 48.57 x 7.4 x 10⁻⁷

= 359.38 x 10⁻⁷ - 359.38 x 10⁻⁷

=0

angle between v and F = 90 degree

4 0
3 years ago
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
Alexxx [7]

Explanation:

It is given that,

Radius of the circular orbit, r=0.53\times 10^{-10}\ m  

Speed of the electron, v=2.2\times 10^6\ m/s

Mass of the electron, m=9.1\times 10^{-31}\ kg

(a) The force acting on the electron is centripetal force. Its formula is given by :

F=\dfrac{mv^2}{r}

F=\dfrac{9.1\times 10^{-31}\times (2.2\times 10^6)^2}{0.53\times 10^{-10}}  

F=8.31\times 10^{-8}\ N

(b) The centripetal acceleration of the electron is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(2.2\times 10^6)^2}{0.53\times 10^{-10}}

a=9.13\times 10^{22}\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
A collision between two large spiral galaxies is likely to produce
Lera25 [3.4K]

A large elliptical galaxy. Hope this helped

5 0
4 years ago
A boy of mass 50 kg walks up a staircase of 10 steps each 15 cm high. Calculate the work done.​
Burka [1]

Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

Workdone = F.S (force x displacement)

Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

Workdone = 50 x 9.8 x 1.5 J

= 735 J

3 0
3 years ago
(responder cual es la correcta)
FromTheMoon [43]

1.c

2.e

3.g

4.a

5.b

6.d

7.f

4 0
3 years ago
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