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4 years ago

Which part of the central nervous system controls reflexes?

Physics

2 answers:

jonny [76]4 years ago

7 0

Answer:

none of these

Explanation:

what actually controlls reflexes is the brain stem

larisa86 [58]4 years ago

6 0

Answer:

spinal cord becuse it does all of the reflexes

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Given that a pipe having a diameter of 1.5 feet and a height of 10 feet, what is the psi at 5 feet ?

grin007 [14]

Answer:

The pressure is 2.167 psi.

Explanation:

Given that,

Diameter = 1.5 feet

Height = 10 feet

We need to calculate the psi at 5 feet

Using formula of pressure at a depth in a fluid

Suppose the fluid is water.

Then, the pressure is

$P=\rho g h$

Where, P = pressure

$\rho$ = density

h = height

Put the value into the formula

$P=1000\times9.8\times1.524$

$P=14935.2\ N/m^2$

Pressure in psi is

$P=2.166167621\ psi$

$P=2.167\ psi$

Hence, The pressure is 2.167 psi.

4 0

3 years ago

An object with a mass M = 250 g is on a plane inclined at 30º above the horizontal and is attached by a string to a mass m = 150

malfutka [58]

Answer:

0.495 m/s

Explanation:

$T$ = tension force in the string connecting the two objects

$M$ = Mass of the object on inclined plane = 250 g = 0.250 kg

$m$ = Mass of the hanging object = 150 g = 0.150 kg

$a$ = acceleration of each object

From the force diagram, force equation for the motion of the object on the inclined plane is given as

$T - Mg Sin30 = Ma\\T = Mg Sin30 + Ma$

From the force diagram, force equation for the motion of the hanging object on the inclined plane is given as

$mg - T = ma\\T = mg - ma$

Using the above two equations

$Mg Sin30 + Ma = mg - ma$

$(0.250)(9.8) Sin30 + (0.250) a = (0.150) (9.8) - (0.150)a$

$a = 0.6125 ms^{-2}$

$h$ = height dropped by the hanging object = 10 cm = 0.10 m

$v$ = Speed gained by the object

Speed gained by the object can be given as

$v = sqrt(2ah)\\v = sqrt(2(0.6125)(0.20))\\v = 0.495 ms^{-1}$

5 0

3 years ago

Gamma rays are a type of very high frequency wave. This means that gamma rays must have a _____.

agasfer [191]

Gamma waves have a short wavelength. The closer the wavelength ( $\lambda$ ) the higher frequency the wave is

4 0

4 years ago

Read 2 more answers

How does a single fixed pulley, like the one seen here, help you do work?

AlexFokin [52]

The correct answer is A.

3 0

4 years ago

Read 2 more answers

A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee

GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

$d=v_ot+\frac{1}{2}at^2$

Now, we transform the total distance the cat would need to travel:

$90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m$

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

$t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots$

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

$1.5m=v_0(\frac{10}{3}s)+\frac{1}{2}(-\frac{9.8m}{s^2})(\frac{10}{3}s)^2\Rightarrow1.5m=v_0(\frac{10}{3}s)+(-\frac{490}{9}m)$ $\Rightarrow\frac{1007}{18}m=v_0(\frac{10}{3}s)\Rightarrow v_0=\frac{1007}{60}\frac{m}{s}\Rightarrow v_0=16.78333\ldots$

So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

5 0

2 years ago