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3 years ago

5

Why does your weight change on the moon

2 answers:

Ludmilka [50]3 years ago

7 0

Answer:

Our weight on moon is less than it would be on Earth due to a difference of the strength of gravity on the moon. The moon's gravitation force is determined by the mass and the size of the moon. ... This means that if you went to the moon you would weigh less, even though your mass stays the same!

Explanation:

Please mark brainliest

lorasvet [3.4K]3 years ago

5 0

Answer:

the moon has different gravitational force.

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What do you mean by shearing stress??

lord [1]

Answer:

Shear stress, force tending to cause deformation of a material by slippage along a plane or planes parallel to the imposed stress. The resultant shear is of great importance in nature, being intimately related to the downslope movement of earth materials and to earthquakes.

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3 years ago

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show answer No Attempt 50% Part (b) Now consider a disk of mass 8 kg with radius 0.55 m. Disk rotates around itself once every 0

hram777 [196]

Answer:

$KE=194.9750\ J$

Explanation:

Given:

mass of disk, $m=8\ kg$

radius of the disk, $r=0.55\ m$

time taken by the disk to complete on rotation, $T=0.35\ s$

<u>We know that rotational kinetic energy is given as:</u>

$KE=\frac{1}{2}\times I.\omega^2$ ............................(1)

Now the angular speed of the disk:

$\omega=\frac{2\pi}{T}$

$\omega=\frac{2\pi}{0.35}$

$\omega=17.952\ rad.s^{-1}$

<u>The moment of inertia of a disk is given as:</u>

$I=\frac{1}{2} m.r^2$

$I=0.5\times 8\times 0.55^2$

$I=1.21\ kg.m^2$

Now using eq. (1):

$KE=\frac{1}{2} \times 1.21\times 17.952^2$

$KE=194.9750\ J$

3 0

3 years ago

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Imagine a spring made of a material that is not very elastic, so that the spring force does not satisfy Hooke’s Law, but instead

Aliun [14]

Answer:

W = -1.152 mJ

Explanation:

given,

F = −α x + β x³

α = 5.2 N/m and β = 700 N/m³

Work done = ?

length of stretch = ?

we know,

W = F . ds

$W = \intF . dx$

$W = \int_0^{0.12} (-\alpha x + \beta x^3).dx$

$W = \int_0^{0.12}(-5.2 x +700 x^3).dx$

$W = [\dfrac{-5.2x^2}{2} +700\dfrac{x^4}{4}]_0^{0.12}$

now,

$W = [\dfrac{-5.2(0.12)^2}{2} +700\dfrac{(0.12)^4}{4}]$

W = -0.001152 J

W = -1.152 mJ

work done by the spring is equal to W = -1.152 mJ

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4 years ago

Does the eruption in the video constitute a pyroclastic flow

densk [106]

If it is the video I am thinking of then Yes

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3 years ago

Determine the empirical formula for a compound that is 36.86% n and 63.14% o by mass.

olga2289 [7]

Answer:

$NO_{1.499}$

Explanation:

Let assume that 100 kg of the compound is tested. The quantity of kilomoles for each element are, respectively:

$n_{N} = \frac{36.86\,kg}{14.006\,\frac{kg}{kmol} }$

$n_{N} = 2.632\,kmol$

$n_{O} = \frac{63.14\,kg}{15.999\,\frac{kg}{kmol} }$

$n_{O} = 3.946\,kmol$

Ratio of kilomoles oxygen to kilomole nitrogen is:

$n^{*} = \frac{3.946\,kmol}{2.632\,kmol}$

$n^{*}= 1.499$

It means that exists 1.499 kilomole oxygen for each kilomole nitrogen.

The empirical formula for the compound is:

$NO_{1.499}$

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4 years ago

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